avoid double click
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i have two panel in ma form. panel1 with button1 on it at location let say x:10,y:10 and panel2 with button 2 on it at location x:10,y:10. what actually button1 do:- it hide panel1 and shows panel2 at the same location. but whenever i click on button1 twice after completion its process it fire button2 click event, plz help me ASAP
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i have two panel in ma form. panel1 with button1 on it at location let say x:10,y:10 and panel2 with button 2 on it at location x:10,y:10. what actually button1 do:- it hide panel1 and shows panel2 at the same location. but whenever i click on button1 twice after completion its process it fire button2 click event, plz help me ASAP
The problem is that the button click event is happening almost immediately - so the second "click" is going to the correct place - the control at that position on the "new" panel. And that will generate a click event for the new button because that is exactly what should happen. If you want to stop it, then 1) Create a class level variable:
private DateTime lastSwap = DateTime.Now;
- In the Button1 click handler, set it:
lastSwap = DateTime.Now;
And then swap panels. 3) In the Button2 click handler, check it and ignore if too soon:
if (DateTime.Now < lastSwap.AddMilliseconds(500)) return;
You can change the 500 to any value you think reasonable - 500 provides half a second.
If you get an email telling you that you can catch Swine Flu from tinned pork then just delete it. It's Spam.
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The problem is that the button click event is happening almost immediately - so the second "click" is going to the correct place - the control at that position on the "new" panel. And that will generate a click event for the new button because that is exactly what should happen. If you want to stop it, then 1) Create a class level variable:
private DateTime lastSwap = DateTime.Now;
- In the Button1 click handler, set it:
lastSwap = DateTime.Now;
And then swap panels. 3) In the Button2 click handler, check it and ignore if too soon:
if (DateTime.Now < lastSwap.AddMilliseconds(500)) return;
You can change the 500 to any value you think reasonable - 500 provides half a second.
If you get an email telling you that you can catch Swine Flu from tinned pork then just delete it. It's Spam.
hello, thaks for your quick response... code is working properly... but it is impossible to implement on big application where there are mre den 20,25 panels and every control takes diff diff tym to execute. hope you get my point. thanks once again.
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hello, thaks for your quick response... code is working properly... but it is impossible to implement on big application where there are mre den 20,25 panels and every control takes diff diff tym to execute. hope you get my point. thanks once again.
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neeraj@max wrote:
are mre den
neeraj@max wrote:
takes diff diff tym
neeraj@max wrote:
hope you get my point.
No, not really. Try cutting out the childish txtspk and talk like a grown up.
hello, thanks for your quick response... code is working properly... but it is impossible to implement on big application where there are more then 20,25 panels and every control takes different time to execute. hope you are getting my point. thanks once again.
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hello, thanks for your quick response... code is working properly... but it is impossible to implement on big application where there are more then 20,25 panels and every control takes different time to execute. hope you are getting my point. thanks once again.
It's not impossible to implement, it's just going to take a while.
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hello, thanks for your quick response... code is working properly... but it is impossible to implement on big application where there are more then 20,25 panels and every control takes different time to execute. hope you are getting my point. thanks once again.
You're missing the point. As a programmer, when you find a solution to the problem, but you have 25 problems - you dont implement the solution 25 times. You implement it once and re-use it 25 times. Think of it this way - if you have 25 customers, you dont write 25 different classes to represent each customer, you implement once class called "Customer" and reuse it 25 times. The same thing applies here, you need a solution which stops a button being clicked within 500ms of another button (personally I think this is an awful solution to your original problem, but hey if it works for you go with it). Write a class which exhibits this behaviour and attach it to every button which requires it.
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You're missing the point. As a programmer, when you find a solution to the problem, but you have 25 problems - you dont implement the solution 25 times. You implement it once and re-use it 25 times. Think of it this way - if you have 25 customers, you dont write 25 different classes to represent each customer, you implement once class called "Customer" and reuse it 25 times. The same thing applies here, you need a solution which stops a button being clicked within 500ms of another button (personally I think this is an awful solution to your original problem, but hey if it works for you go with it). Write a class which exhibits this behaviour and attach it to every button which requires it.
@J4amieC thanks for your 25 customer and single solution example... but this solution is suitable for 2,3 panel only becuase diffrent buttons have diffrent tasks and process time so we cant fix the 500ms for every event. anyways i am looking for more suitable solution..... if you come to know any, let me know.
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@J4amieC thanks for your 25 customer and single solution example... but this solution is suitable for 2,3 panel only becuase diffrent buttons have diffrent tasks and process time so we cant fix the 500ms for every event. anyways i am looking for more suitable solution..... if you come to know any, let me know.
The 500ms had nothing to do with whatever task the button does, it had to do with stopping a quick double click operating a button which appears after the first click. It should not matter what the second button does! Anyway your original question asked about 2 panels, and you got a solution to the question as stated. Ask the right question, and you'll get the right answer.
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The 500ms had nothing to do with whatever task the button does, it had to do with stopping a quick double click operating a button which appears after the first click. It should not matter what the second button does! Anyway your original question asked about 2 panels, and you got a solution to the question as stated. Ask the right question, and you'll get the right answer.
http://www.youtube.com/watch?v=bpojl4XMweo&feature=g-upl above link will explain you my problem very clearly.
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http://www.youtube.com/watch?v=bpojl4XMweo&feature=g-upl above link will explain you my problem very clearly.
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leave it then i will solve it by myself ...
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i have two panel in ma form. panel1 with button1 on it at location let say x:10,y:10 and panel2 with button 2 on it at location x:10,y:10. what actually button1 do:- it hide panel1 and shows panel2 at the same location. but whenever i click on button1 twice after completion its process it fire button2 click event, plz help me ASAP
by ignoring queued mouse events. i got my answer.
@everybody: thank you every one for your suggestions.
