A question to dust_dex

Hakan Bulut

Well.. now how do i prevent adding the numbers of array elements value, array elements only among themselves, I just wanted to combine random.. Output is: 19, 0 23, 1 20, 2 19, 3 34, 4 45, 5 it must be: 19, 23, 20, 19, 34, 45 Why does it wrote the numbers of random array and how do i prevent the same number selection..¿

Quickly remove the shameless

Hakan Bulut

I have to special thanks for all ur helps.

Hakan Bulut

I tried the following lines at least.. have you got an idea about this statement?

document.write("<BR><BR>" + "Combination is :" + "<BR>");
do(q) { z += 1;
var q = Math.round(Math.random()* 11);
if(q==q) {return q;}
document.write(rec[q] +", "+ z);
} while(z==6);

Hakan Bulut

Is there something to way some simple code to do this?

dusty_dex

Well you aren't putting the (value of) the z variable into the array. Only showing its value. remove the

+ z +" "

from document.write

"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

dusty_dex

replace with this.

var lucky = \[\];
var rec = \["19","20","21","40","41","45","12","23","34","36","37","46"\];
document.write("Weekly records for 2 week : ");
for(var i=0; i<12; i++) {
    document.write(rec\[i\] + ",");
}

document.write("

");

var z=0;
do {
    var q = Math.round(11 \* Math.random());
    if(!taken\[ rec\[q\] \]) {
        lucky\[z\] = rec\[q\];
        taken\[ rec\[q\] \] = true;
        document.write(lucky\[z\] + "

");
z++;
}
} while (z < 6);
</script>

this line:

if(!taken[ rec[q] ])

checks if NOT taken (! = not)

"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

dusty_dex

Just letting you know what your errors here are. See my other post for new code.

do(q)

can't use expressions at the top of do loop *(q)*, just use

do {

z is not declared with var *and* initialised with a value. var z = 0;

z +=1; // z (undefined) +1 is still undefined

you don't need the { } braces for a single statement..

if(q==q) return q;

but, q==q just evaluates to true so you might as well have just written this

return q; // if (q==q) {return q;}

I am not able to reply very quickly. On a training course for another 10 days. Be patient. Please keep trying to write new code as it is easier for me to guess what you are doing. :)

"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

Hakan Bulut

Excellent code thanks a lot.

Hakan Bulut

Finally, ask you for anything more in a array of 12 elemented to 49 membered Argument want to match, you can also help me in this topic? JavaScript writing is so hard really. Thank you for your help. I tried the following lines:

var arrNumbers = [49];
var arrOutside = [];
var arrInside = ["19","20","21","40","41","45","12","23","34","36","37","46"];
var z=0;
for(var i=0; i<12; i++) { arrInside[i]=false; }

for(var j=49; j>0; --j)
{
arrNumbers[j]=j;

if(arrNumbers[j] != arrInside[i]) {
document.write(arrNumbers[j]=arrOutside[z], + ", ");
arrInside[i] = true;
z++;
}
}

if this is what special things I did not want to deal with it.. I do not want to discuss whom it is could not be shy

dusty_dex

Please explain what inside & outside mean. inside what? outside what? arrNumbers = [49]; // array length = 1 ??? I'm guessing this is what you intended arrNumbers = new Array(49); Also, you can't assign (=) inside of document.write()

arrOutside[j]=j

arrNumbers[j] = arrOutside[z]

did you mean to show arrNumbers and arrOutside, or copy from one to another? this does not make sense.

arrNumbers[j] && arrInside[i] = true;

What other programming language do you know? Because, it might be easier if you write your code in a computer language that you are familiar with. I will be able to figure it out.

"It's true that hard work never killed anyone. But I figure, why take the chance." - Ronald Reagan That's what machines are for. Got a problem? Sleep on it.

Hakan Bulut

It flags to the 49 numbers of numeric lotto arrInside is the numbers two week of and arrOutside is other numbers of 49 that is The number 49 is the number of remaining ..previously worked on the platform of Visual C++ 6.0.. I am thinking you are right JavaScript language is not completely literal a language because of it's called name as script ... arrInside arrOutside are instead of lucky or unlucky they may also like the your previous thread is to be