Bit concatenation in C++

[Manoj7390]

But i need to concatenate the bits which are in different variables. how to concatenate those.. Since i cannot use shift operator here because of binary.

[Manoj7390]

Can you please suggest me a program to convert a string into binary, that store in char data type.

[Chris Losinger]

Richard MacCutchan wrote:

If you will not use the shift operators to store the three bits together then you cannot store them.

int Answer = u * 4 + p * 2 + q

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[Chris Losinger]

char * p = "101";
char * pEnd;
int val = strtol(p, &pEnd, 2);
char charval = (char)val;

this may fail if p is more than 7 bits long (since that could overflow a signed char).

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[Lost User]

Which the compiler will almost certainly optimise into shift operations.

Use the best guess

[Lost User]

Manoj7390 wrote:

i cannot use shift operator here because of binary.

What on earth are you talking about? I have shown you exactly how to concatenate these fields into a three bit value. If you really cannot understand that simple operation then I don't think you are going to get very far with this project.

Use the best guess

[Chris Losinger]

possibly. but that extends the definition of "you" quite a bit. int Answer = u + u + u + u + p + p + q;

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[David Crow]

Something like:

int answer = (u*100) + (p*10) + q;

"One man's wage rise is another man's price increase." - Harold Wilson

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[Lost User]

Chris Losinger wrote:

that extends the definition of "you" quite a bit.

:confused:

Use the best guess

[Chris Losinger]

you originally wrote "If you will not use the shift operators to store the three bits together then you cannot store them." that's the "you". i think it's reasonable to differentiate between what the programmer writes and what the compiler does.

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[Lost User]

Sorry, but I don't understand what point you are trying to make.

Use the best guess