How to return GetResponseStream in xml?

[miss786]

I am trying to create web request, which sends XML via POST call and would like to return the response back in XML. I am having a little difficulty with the response back xml, as I am little I unsure how do I set that up int he code below. here is my attempt:

 // Attempt to receive the WebResponse to the WebRequest.
        using (HttpWebResponse hwresponse = (HttpWebResponse)hwrequest.GetResponse())
        {
            statusCode = (int)hwresponse.StatusCode;
            if (hwresponse != null)
            { // If we have valid WebResponse then read it.
                using (StreamReader reader = new StreamReader(hwresponse.GetResponseStream()))
                {
                    // XPathDocument doc = new XPathDocument(reader);
                    string responseString = reader.ReadToEnd();
                    if (statusCode == 201 )
                    {

                      //  var response = new XElement("Status",
                       //    new XElement("status\_code", statusCode),
                      //     new XElement("resources\_created",
                      ////         new XElement("Link"),
                      //         new XElement("href"),
                      //         new XElement("title")
                      //         ),

                      //         new XElement("warnings")

                       //        );

                        XmlDocument xmlDoc = new XmlDocument();
                        xmlDoc.Load(responseString);
                        XmlNodeList address = xmlDoc.GetElementsByTagName("Status");

                        responseData = xmlDoc.ToString();
                        reader.Close();

                    }
                }
            }

            hwresponse.Close();

        }

    }
    catch (WebException e)
    {
        if (e.Status == WebExceptionStatus.ProtocolError)
        {
           // XmlDocument xmlDoc = new XmlDocument();
          //  XmlNodeList address = xmlDoc.GetElementsByTagName("Status", statusCode);
           // xmlDoc.Load(xmlDoc);
        }



     //   if (e.Status == WebExceptionStatus.ProtocolError)
     //   {
          //  responseData = "Status Code : {0}" + ((HttpWebResponse)e.Response).StatusCode + "Status Description : {0}" + ((HttpWebResponse)e.Response).StatusDescription;