Doubt

[CPallini]

You could make some reasoning about row number and to-be-produced pattern:

0 1###1
1 33#33
2 55555
3 33#33
4 1###1

The first point could be observig that

pattern(0) == pattern(4)
pattern(1) == pattern(3)
pattern(2) == pattern(2)

all hold true. In other words

pattern(k) == pattern(4-k)

hold true for

k = 0, 1 , 2;

Go on and post specific questions when you are not able to continue.

[User 11745560]

#include #include int main() { int num=3; for(int r1=1;r1<=num;r1++) { for(int c1=1;c1<=r1;c1++) { printf("*"); } for(int s1=r1;s1=1;r2--) { for(int c2=1;c2<=r2;c2++) { printf("*"); } for(int s1=r2;s1

[User 11745560]

#include #include int main() { int num=3; for(int r1=1;r1<=num;r1++) { for(int c1=1;c1<=r1;c1++) { printf("*"); } for(int s1=r1;s1=1;r2--) { for(int c2=1;c2<=r2;c2++) { printf("*"); } for(int s1=r2;s1

[User 11745560]

Sir Thanks for your advice Finally done!!! but check it once and report me back if any problem is there in coding #include #include int main() { int num=3; for(int r1=1;r1<=num;r1++) { for(int c1=1;c1<=r1;c1++) { printf("*"); } for(int s1=r1;s1=1;r2--) { for(int c2=1;c2<=r2;c2++) { printf("*"); } for(int s1=r2;s1

[Lost User]

What result do you get?

[User 11745560]

* * ** ** ****** ** ** * *

[Lost User]

OK, so just replace the stars with the numbers in each case and you have your result.

[User 11745560]

yes sir the actual result is this #include #include int main() { int num=5; for(int r1=1;r1<=num;r1+=2) { for(int c1=1;c1<=r1;c1++) { printf("%d",r1); } for(int s1=r1;s1=1;r2-=2) { for(int c2=1;c2<=r2;c2++) { printf("%d",r2); } for(int s1=r2;s1

[Lost User]

Your loop values are slightly off. You should be counting 1 - 3 - 5 - 3 - 1, and printing the numeric values in each line rather than stars. Your main loops should be something like:

int num = 5;
int index;
// go from 1 to 5
for (index = 1; index <= num; index += 2)
{
// print the first set of values
printf("%d\n", index); // just to show the number
}
// already printed the 5 set, so go from 3 to 1
for (index = num - 2; index > 0; index -= 2)
{
// print the last set of values
printf("%d\n", index);
}

[User 11745560]

Ok sir Thnak's and could you please give some examples to practise in this pattern??

[Lost User]

That is an example, your job is to fill in the fine detail. You will learn much more by trying it yourself than if someone else writes it for you. As an exercise you can try different values of num also.