variable undefined

[wfzen]

I want to extract a video name from XML and put it in the URL parameter. I copied the XML reading code from w3school. See below:

//var videoName; the name of the video
var tPath = ... the URL to the XML
var var2 = ... the filename of an XML
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
myFunction(this);
}
};
xmlhttp.open("GET", tPath, true);
xmlhttp.send();
function myFunction(xml) {
var x, xmlDoc, videoName;
xmlDoc = xml.responseXML;
x = xmlDoc.getElementsByTagName("videoName")[0];
videoName = (x.textContent);
alert (videoName);
}
var playerURL = "http://" + getCookie("MediaServerGeneral") + "/IVP/demo.htm?XMLName=" + var2 + "&MediaFileName=" + videoName;

I see the name of the video in alert. but the playerURL has videoName shown as undefined. my XML is like this, and I'm trying to pick up "videoName.mp4":

videoName.mp4

What is wrong with the script? Thanks,

[Lost User]

See XML DOM getElementsByTagName() Method[^], I think you need to go one level further to get the value.

[Rahul VB]

Just try to fetch the value of "x" in the below code outside "myFunction"

x = xmlDoc.getElementsByTagName("videoName")[0];

I am wondering, if the value of "x" is dying out. I also cant see the closing braces of "myFunction" or no return value of "x" from the function. Is the below code a part of "myFunction" ?

var x, xmlDoc, videoName;
xmlDoc = xml.responseXML;
x = xmlDoc.getElementsByTagName("videoName")[0];
videoName = (x.textContent);
alert (videoName);

var playerURL = "http://" + getCookie("MediaServerGeneral") + "/IVP/demo.htm?XMLName=" + var2 + "&MediaFileName=" + videoName;

If so, just try out reading the value of the element out side the function and see. Please let me know the result once. Thanks

[wfzen]

Thank you for your help. I forgot to copy the } after the alert(videoName). So myFunction ends after alert. var playerURL... is not part of the function. I'm trying to take the script out of the function. I'll post back the result.