Why -nan values appear
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I perform some experiments with the cpp code and I got -nan values. Can anybody tell why I might get these values
Because the math operations performed by your code result in a NaN? You cast an integer with at least the relevant most signficant bits set to
floatordouble? You have a buffer overflow writing such a value to the memory of afloatordouble? Without seeing code, we can't tell you for sure. -
I perform some experiments with the cpp code and I got -nan values. Can anybody tell why I might get these values
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I perform some experiments with the cpp code and I got -nan values. Can anybody tell why I might get these values
Because what ever you are doing, the result is not a number.
"One man's wage rise is another man's price increase." - Harold Wilson
"Fireproof doesn't mean the fire will never come. It means when the fire comes that you will be able to withstand it." - Michael Simmons
"You can easily judge the character of a man by how he treats those who can do nothing for him." - James D. Miles
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I perform some experiments with the cpp code and I got -nan values. Can anybody tell why I might get these values
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2 most likely reasons: Invalid math e.g. division by zero, or use of uninitialized variables. Without seeing your code, and input, we can't know.
ahem... Division by zero in general produces a (signed)
Inf, not aNaN.Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012
