SerialPort DataReceived Event Read Byte ?
-
So you just need to keep reading until you have all the data. As OriginalGriff points out below, the data does not all arrive at once.
Only the manufacturer of 41 bytes will deliver the future in a single time. If it does not come in one go as you have stated, how can I get it in the order of the results? So how do I get to 8 + 8 + 8 + 8 in order of incoming results?
-
No - we aren't here to do all your work for you. If you don't know what you are doing - and it doesn't sound like you have any idea about communications - then you need to start reading and learn, because this is the really easy stuff! If you don't understand what is happening here, nothing else about this job will make any sense, and I will end up doing it all for you. And trust me, I'd have to charge you for doing your work for you! :laugh:
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!
:) In this case you are right, I've searched too much But I did not do what I did, I believe that if I can at least understand the logic of this, I will be able to do so without any problem. On the Yinede You Are So Glad to Help Me in This Concern?
-
:) In this case you are right, I've searched too much But I did not do what I did, I believe that if I can at least understand the logic of this, I will be able to do so without any problem. On the Yinede You Are So Glad to Help Me in This Concern?
Stop "searching for the solution" and start reading up on how it all works - this is stuff you need to know in order to work with comms effectively.
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!
-
Hello, I would like to ask you to share information on a subject, I am experiencing a problem related to data transmission and data retrieval on an Indicator device connected to a serial port on a project I am developing. Code I Write For Trial Purpose As Below, SerialPortTLB_DataReceived Event Overflow Should Not Send on Textbox as Byte, How can I print the incoming data as Bytes? I'm Waiting For You About This Issue, Good Work ...
using DevComponents.DotNetBar.Metro;
using System;
using System.Windows.Forms;namespace VeriOkuma
{
public partial class VeriOkuma : MetroForm
{
public VeriOkuma()
{
InitializeComponent();
}private void BTNVeriGonder\_Click(object sender, EventArgs e) { if (!SerialPortTLB.IsOpen) SerialPortTLB.Open(); SerialPortTLB.Write(System.Convert.ToChar(2).ToString() + System.Convert.ToChar(1).ToString() + "DNG" + System.Convert.ToChar(13).ToString()); } private void VeriOkuma\_Load(object sender, EventArgs e) { if (SerialPortTLB.IsOpen) { SerialPortTLB.Close(); } } private void SerialPortTLB\_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e) { if (!SerialPortTLB.IsOpen) SerialPortTLB.Open(); TXBGelenVeri.Text = SerialPortTLB.ReadExisting(); SerialPortTLB.Close(); } }}
-
-
Only the manufacturer of 41 bytes will deliver the future in a single time. If it does not come in one go as you have stated, how can I get it in the order of the results? So how do I get to 8 + 8 + 8 + 8 in order of incoming results?
Serial devices present their data in "chunks", and each chunk may be anything from a single byte to a complete message. This is a feature of serial IO that the programmer needs to understand and deal with. Your input routine needs to capture however much data is presented each time, and build the message buffer by appending the latest 'chunk' to whatever has already been read in. When you are certain that you have all the available data you can go and process it. If the manufacturer tells you that you will receive 41 bytes, then you must keep reading until your message has received that number of bytes.
-
Serial devices present their data in "chunks", and each chunk may be anything from a single byte to a complete message. This is a feature of serial IO that the programmer needs to understand and deal with. Your input routine needs to capture however much data is presented each time, and build the message buffer by appending the latest 'chunk' to whatever has already been read in. When you are certain that you have all the available data you can go and process it. If the manufacturer tells you that you will receive 41 bytes, then you must keep reading until your message has received that number of bytes.
The Problem I'm Having Problem With, What's The Value 8 Bytes Coming Up and How Can I Keep Reading the Restored Values? How Do I Write a Code?
-
I have used the Thread Function, and now Delete
Doesn't matter - the DataReceived event is never fired on the UI thread, so you will get an cross thread exception anyway. See what I mean about needing to know this stuff?
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay... AntiTwitter: @DalekDave is now a follower!
-
The Problem I'm Having Problem With, What's The Value 8 Bytes Coming Up and How Can I Keep Reading the Restored Values? How Do I Write a Code?
ibrahimayhans wrote:
How Do I Write a Code?
First you need to understand the problem.
Set an index to the start of your receive buffer
Do
Read some data using the index to position it at the correct point in the buffer
Add the count of bytes read to the offset index
While index < 41
// when the index reaches 41 you have all the data (bytes 0 to 40) -
Hello, I would like to ask you to share information on a subject, I am experiencing a problem related to data transmission and data retrieval on an Indicator device connected to a serial port on a project I am developing. Code I Write For Trial Purpose As Below, SerialPortTLB_DataReceived Event Overflow Should Not Send on Textbox as Byte, How can I print the incoming data as Bytes? I'm Waiting For You About This Issue, Good Work ...
using DevComponents.DotNetBar.Metro;
using System;
using System.Windows.Forms;namespace VeriOkuma
{
public partial class VeriOkuma : MetroForm
{
public VeriOkuma()
{
InitializeComponent();
}private void BTNVeriGonder\_Click(object sender, EventArgs e) { if (!SerialPortTLB.IsOpen) SerialPortTLB.Open(); SerialPortTLB.Write(System.Convert.ToChar(2).ToString() + System.Convert.ToChar(1).ToString() + "DNG" + System.Convert.ToChar(13).ToString()); } private void VeriOkuma\_Load(object sender, EventArgs e) { if (SerialPortTLB.IsOpen) { SerialPortTLB.Close(); } } private void SerialPortTLB\_DataReceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e) { if (!SerialPortTLB.IsOpen) SerialPortTLB.Open(); TXBGelenVeri.Text = SerialPortTLB.ReadExisting(); SerialPortTLB.Close(); } }}
Hi, serial communication can be very hard, and it can be quite easy; it all depends on circumstances: how high the transmission rate is, how big the gap is in between messages, etc. Here are three pointers, assuming the peripheral uses printable text: 1. Always use a terminal emulator to get acquainted with your peripheral's behavior. It will help you in checking the hardware aspects and overall settings of your port, and it will help you in understanding the message flow. 2. the
DataReceivedevent fires whenever it wants, which could be after receiving 1 byte, or 39 bytes, or whatever. It does not care about what you expect as a message, it only knows about individual bytes and several levels of buffering inside Windows. As a result it isn't very useful except in simple cases: If your messages are far apart, which gives you some time to waste, the easiest approach is to get started by theDataReceivedevent, then wait (withThread.Sleep) sufficiently long so the entire message should be received by now, and then use ReadExisting. The required delay equals maximum string length * character time, which obviously depends on the baud rate used (say 1 msec at 9600 baud). Warning: Windows timing isn't always very accurate, so add a spare 20 msec or so. 3. TheDataReceivedevent gets handled on an arbitrary thread (actually one from the ThreadPool) but absolutely NOT on the GUI thread (read more: Asynchronous operations run on ThreadPool threads[^]); therefore, you are not allowed to touch any of your GUI Controls inside the DataReceived handler. The proper solution is by usingControl.InvokeRequiredandControl.Invoke(read more: Invalid cross-thread operations[^]). NEVER use Control.CheckForIllegalCrossThreadCalls In more complex situations I tend to avoid theDataReceivedevent, instead I'd use an explicit Thread and perform blocking reads and a buffering scheme. Sometimes a BackgroundWokrer can do the job. Hope this helps. :) PS: Don't trust the default settings of SerialPort, always explicitly set properties such as Encoding, NewLine, etc.
