Problem using strings

[k5054]

You have: char *s3 = "...". Although s3 is declared as char * the type of the string is const char *. Use char s3[] = "..." instead.

[David Crow]

If I were to hazard a guess, I'd say it has to do with aux being destroyed (i.e., going out of scope) once my_strdelupper() returns.

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[Joe Woodbury]

This line of code puzzles me:

*(s + i) != '\0' < len

It probably should be:

i < len

A second problem is that you are doing the copy only on !isupper, when you should be doing it always as soon as an uppercase character is detected. A third problem is the strcpy() at the end. It's pointless. A fourth problem is that you are returning a pointer to the a stack value which becomes invalid because the call to printf is likely overwriting it and is likely causing a fault.

[Lost User]

Try this:

char* my_strdelupper(char* s){
int i, len;
char* sl;

len = strlen(s);
sl = (char\*)malloc(len+1); // space for the converted string
i = 0; // index to the converted string buffer
while (\*s != '\\0'){
    if (!isupper(\*s)){
        sl\[i++\] = \*s; // copy lower case letters
    }
    s++;
}
sl\[i\] = '\\0';
printf("%s\\n", sl);

return sl;

}

[Rodrigo Lourenco]

I'm working with C

[Rodrigo Lourenco]

You are correct, that was one mistake, but it should be *(s + i) != '\0' because I am searching for the end of line.

[Rodrigo Lourenco]

The stupid thing is that I can't use malloc, so I made a char array with fixed size to overcame that problem.

[Rodrigo Lourenco]

I think you are correct, but I tried to copy aux to s and didn't work, now I changed the code to send an array, them befour I leave I copy using srtcpy aux to s, and it's working.

[Rodrigo Lourenco]

It worked thanks

[Rodrigo Lourenco]

Thank you, for all, it was a great help. The problem was solved by:

#include #include #include #include #define false 1
#define true 0

char* my_strdelupper(char* s){

  int i,j, len;
  char aux\[100\];
  char debuging;

  len = strlen(s);
  j = 0;
  for (i = 0; \*(s + i) != '\\0'; i++){
      if (!isupper(\*(s+i))){
          debuging = \*(s + i);
          \*(aux + j) = debuging;
         j++;
      }
  }
  \*(aux + j) = '\\0';

  strcpy(s, aux);
  return s;

}

int main()
{
char s3[]="Maria, TU sabes que TU éS o meu \"Grande Amor\"";
printf("%s\n",my_strdelupper(&s3[0])); /* aria, sabes que é s o meu "rande mor " */

return 0;
}

[jschell]

As a note - you define 'len' but you don't use it. Presumably the assignment does not say otherwise, using that would make your code simpler.

[CPallini]

Note you don't need extra storage, the function may change the string in place:

char * remove_upper( char * s)
{
char * p, *q;

for (p = q = s; *p != '\0'; ++p)
if ( ! isupper(*p) )
*q++ = *p;

*q = '\0';
return s;
}

[Peter_in_2780]

Taken from K&R 1st ed? Certainly has that feel> :laugh: ;P

Software rusts. Simon Stephenson, ca 1994. So does this signature. me, 2012

[CPallini]

It is the Wonderful C programming language, of course has such a feel. In any case, were Dennis and Brian the ones who plagiarized my programs. :-D

[Member_14494321]

As I have not clear idea about the std but yes this library used in most of the cases. [Fixed] Dell Printer Error 016 302 | Error Code 0x[^] helped me to get the solution.

[John R Shaw]

I was begging to think no one here was thinking. Thanks

INTP "Program testing can be used to show the presence of bugs, but never to show their absence." - Edsger Dijkstra "I have never been lost, but I will admit to being confused for several weeks. " - Daniel Boone