Regex Expression to extract everything following a string and before a space

[Member_14572415]

Hi all, I am looking for a regular expression to extract everything following a string and before a space. Please see the example below. Order placed at the store. Order Date: 01/12/2017 This was completed. From the above string, I would like to extract the following. Order Date: 01/12/2017 Thanks, Ana

[Lost User]

How about: Order Date: \d\d\/\d\d\/\d\d

[Richard Deeming]

Perhaps with a couple of extra \ds to cope with the four-digit year? :)

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Richard Deeming]

If you want to include the "Order Date: " in your extracted value:

Order Date:\s*[^\s]+

If you just want the "01/12/2017", and you're using C#, then:

(?<=Order Date:\s*)[^\s]+

(Other regular expression processors may also support "zero-width positive lookbehind" assertions. But Javascript, for example, doesn't.)

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Member_14572415]

Hi Richard, Thanks for your response! Since I need the order date, I tried using "Order Date:\s*[^\s]+" per your post above, and it is pulling text after the date, time and AM/PM. So, I would like to pull everything before the date, time and AM/PM. Any suggestions would be appreciated. Thank you! Ana

[Member_14572415]

So, my string is like the following. Order placed at the store. Order Date: 01/12/2017 10:54 AM This was completed. I would like to pull "Order Date: 01/12/2017 10:54 AM" Hope this helps. Thanks, Ana

[Member_14572415]

Hi Richard, My string is like the following. Order placed at the store. Order Date: 01/12/2017 10:54 AM This was completed. I would like to pull "Order Date: 01/12/2017 10:54 AM" Hope this helps. Thanks, Ana

[Lost User]

Oops again. :doh:

[Lost User]

If you take my original Order Date: \d\d\/\d\d\/\d\d , plus Richard Deeming's reply to me \d\d for the rest of the year, then you should be able to work out what else is needed. And you can test your expression online at RegExr: Learn, Build, & Test RegEx[^].

[Richard Deeming]

You specifically said you wanted to extract the text up to the first space, and there is a space between 2017 and 10:54. And then another space between 10:54 and AM. If the date and time is always in the same format - which doesn't match the example you gave in your original message - then try something like:

Order Date: \d\d\/\d\d\/\d\d\d\d \d\d:\d\d [AP]M

Demo[^]

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Member_14572415]

Hi Richard, Sorry for the confusion. I tried the expression that you posted and it works perfectly! Also, I would like to pull "Name is: Tia" from the following string: My friend's Name is: Tia She lives in Argentina. Thanks so much, Ana

[Member_14572415]

Yes, that work! Thanks

[Richard Deeming]

Only one name, with no spaces?

Name is: [^\s]+

Demo[^]

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer

[Member_14572415]

Hi, I tried "Name is: [^\s]+" but I am getting back the text after the space as well. How can I fix this? Thanks, Ana

[phil o]

You could try "Name is:\s([^\s]+).*$". The result will be in the first numbered group of the result.

string input = "My friend's Name is: Tia She lives in Argentina.";
Regex r = new Regex(@"Name is:\s([^\s]+).*$");
string name = r.Match(input).Groups[0].Value;

while (!(success = Try()));

[Richard Deeming]

Then there's either a bug with the regular expression engine you're using, or there's something wrong with your code. [^\s]+ explicitly excludes any spaces. That pattern will match the first run of characters which are not spaces to appear after the prefix "Name is: ".

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"These people looked deep within my soul and assigned me a number based on the order in which I joined." - Homer