hello, good day, does anyone know how to solve this problem? It would help me a lot if you could explain how to do it

[Member_15792429]

def ListOfLists(list):
'''
This function receives a list, which can contain elements that are themselves lists and
returns those items separately in a single list.
If the parameter is not of type list, it must return null.
Receive an argument:
list: The list that can contain other lists and is converted to a
list of unique or non-iterable elements.
Ex:
ListOfLists([1,2,['a','b'],[10]]) should return [1,2,'a','b',10]
ListOfLists(108) should return null.
ListOfLists([[1,2,[3]],[4]]) should return [1,2,3,4]

[Lost User]

You can use the Built-in Functions type() — Python 3.10.7 documentation[^] builtin function to find out what each item is.

[Reverend Jim]

A tad late to the party but a recursive approach seems to work.

def Collapse(lst):

result = \[\]

for item in lst:
    if type(item) == list:
        result.extend(Collapse(item))
    else:
        result.append(item)

return result

a = [1, [2, 3, [3.1, 3.2]], 4]
b = Collapse(a)

print(a)
print(b)