XML DOM get current position Node

[Anonymous]

When i search a certain xml-file using "selectNodes("//ROOT/BLA")" and i receive the found nodes. Is it possible to get iterate through those found nodes and retrieve their current position in the xml-tree? (remember that this is DOM and not XSLT, so "position()" and all that crap won't work). Any help is greatly appriciated.

[Philip Fitzsimons]

by position I presume you mean name - you could use: XmlNodeList results = document.SelectNodes(""//root/bla"); foreach (XmlNode result in rtesults) {   Console.Write("found {0} value = '{1}'", GetNodeName(result), result.value); } string GetNodeName(XmlNode node) {   string result = node.LocalName;   if (node.Parent != null)     result = GetNodeName(node.Parent) + "/" + result;   return result; } if you want the position then just change the above function to count previousSiblings: string GetNodePosition(XmlNode node) {   int previousSiblings = 0;   for (XmlNode previous_node = node.PreviousSibling; previous_node != null; previous_node = previous_node.PreviousSibling)     previousSiblings++;   string result = previousSiblings.ToString();   if (node.Parent != null)     result = GetNodeName(node.Parent) + "/" + result;   return result; } hope this helps

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"When the only tool you have is a hammer, a sore thumb you will have."

[Anonymous]

yeah...i thought i would have to write my own function to calculate the current position. I was hoping i overlooked something and that it was possible to retrieve the index/position directly from a found node. Thanks though, for your reply.