Getting an intersect of a color
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I need to get the intersection of Green and Yellow in ARGB format Is there a function for this. And yes I know Color.GreenYellow exists but I need to know how to get intersections to achieve other mid way points. nick I'm not an expert yet, but I play one at work. Yeah and here too.
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I need to get the intersection of Green and Yellow in ARGB format Is there a function for this. And yes I know Color.GreenYellow exists but I need to know how to get intersections to achieve other mid way points. nick I'm not an expert yet, but I play one at work. Yeah and here too.
Yellow is green and red together, from memory. Whatever it is, get the RGB value of red, green is obviously 0, 255, 0, and build a lookup table, or a function. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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Yellow is green and red together, from memory. Whatever it is, get the RGB value of red, green is obviously 0, 255, 0, and build a lookup table, or a function. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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but how do I calculate an intersection? I'm not an expert yet, but I play one at work. Yeah and here too.
Well, assuming that yellow is RGB 255, 255, 0, and green is obviously 0, 255, 0, there are 255 intersection points. Like so: 0, 255, 0 1, 255, 0 2, 255, 0 3, 255, 0 You get the idea. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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Well, assuming that yellow is RGB 255, 255, 0, and green is obviously 0, 255, 0, there are 255 intersection points. Like so: 0, 255, 0 1, 255, 0 2, 255, 0 3, 255, 0 You get the idea. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
Yes but since green is 0,128,0 and green yellow is 0,173,28 and yellow is 255,255,0 a simple matter of adding 1 to red does not get me any closer to the intersection since its not a linear equation. I was hoping someone would know a math formula to calculate the intersection of the three planes basically. nick I'm not an expert yet, but I play one at work. Yeah and here too.
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Yes but since green is 0,128,0 and green yellow is 0,173,28 and yellow is 255,255,0 a simple matter of adding 1 to red does not get me any closer to the intersection since its not a linear equation. I was hoping someone would know a math formula to calculate the intersection of the three planes basically. nick I'm not an expert yet, but I play one at work. Yeah and here too.
How can green be 0, 128, 0 ? It is green, as is any value with 0 red and 0 blue, but hard green is 255, surely ? In any case, the system works the same way, forget greenyellow, it's obviously not the point halfway between the other two. Instead, add 2 to your red value for every 1 you add to your green value. Write up a program that does that and draws a gradient and see how it looks. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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How can green be 0, 128, 0 ? It is green, as is any value with 0 red and 0 blue, but hard green is 255, surely ? In any case, the system works the same way, forget greenyellow, it's obviously not the point halfway between the other two. Instead, add 2 to your red value for every 1 you add to your green value. Write up a program that does that and draws a gradient and see how it looks. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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thanks By the way those are colors from the color namepsace. so obviously thier not dark colors I'm not an expert yet, but I play one at work. Yeah and here too.
Yeah, I guessed where they were from. I guess they have a dark green or something... Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder
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I need to get the intersection of Green and Yellow in ARGB format Is there a function for this. And yes I know Color.GreenYellow exists but I need to know how to get intersections to achieve other mid way points. nick I'm not an expert yet, but I play one at work. Yeah and here too.
use hue-saturation-brightness...
"When the only tool you have is a hammer, a sore thumb you will have."
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use hue-saturation-brightness...
"When the only tool you have is a hammer, a sore thumb you will have."
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do you have a link or some help for explanation I'm not an expert yet, but I play one at work. Yeah and here too.
Color.GetHuehttp://wombat.doc.ic.ac.uk/foldoc/foldoc.cgi?hue,+saturation,+brightness[^]
"When the only tool you have is a hammer, a sore thumb you will have."
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I need to get the intersection of Green and Yellow in ARGB format Is there a function for this. And yes I know Color.GreenYellow exists but I need to know how to get intersections to achieve other mid way points. nick I'm not an expert yet, but I play one at work. Yeah and here too.
Treat each color value as a percentage 0=0%, 255=100% So, a certain color might be (20%, 30%, 90%) in RGB if you want to intersect that with another color (100%, 60%, 0%) the intersection will be the averages: (60%, 45%, 45%) Make sense?
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Treat each color value as a percentage 0=0%, 255=100% So, a certain color might be (20%, 30%, 90%) in RGB if you want to intersect that with another color (100%, 60%, 0%) the intersection will be the averages: (60%, 45%, 45%) Make sense?
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heres a rough equation i got from my friend: average the "Reds" - aa+11= bb bb/2 = 5D bb+22 = DD dd/2 = 6e cc+33 = ff ff/2 = 7f so the average =c #aabbcc and #112233 = #5D6E7F I'm not an expert yet, but I play one at work. Yeah and here too.
Yeah, it's pretty much the same thing. (Ra + Rb)/2 = Ri (Ba + Bb)/2 = Bi (Ga + Gb)/2 = Gi It makes sense since if you intersect a red line (255,0,0) with a black line (0,0,0) then the result should be a darker red line (128,0,0)
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I need to get the intersection of Green and Yellow in ARGB format Is there a function for this. And yes I know Color.GreenYellow exists but I need to know how to get intersections to achieve other mid way points. nick I'm not an expert yet, but I play one at work. Yeah and here too.
just mix them Color c1=Color.Green; Color c2=Color.Yellow; Color mix=Color.FromArgb( (c1.r+c2.r)/2,(c1.g+c2.g)/2,(c1.b+c2.b)/2); //Roger