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solving Brouncker's fraction expansion?

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a_hyams

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#1

Anybody have any idea how to solve Brouncker's continued fraction expansion using a recursive function??? ie: 4/pie = 1 + 1^2/(2+ (3^2/2+ (5^2/2+....))). Thanks.;P a_hyams
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A a_hyams

Anybody have any idea how to solve Brouncker's continued fraction expansion using a recursive function??? ie: 4/pie = 1 + 1^2/(2+ (3^2/2+ (5^2/2+....))). Thanks.;P a_hyams
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ZoogieZork

wrote on last edited by

#2

Smells like homework... what have you done so far? Also, it's 'pi', not 'pie' :) - Mike
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