time in ascii

[styve]

I'm using time.h, to get time of the day. In my code it is converted into number so it is possible to read the time. But I will have it in ascii format. I dont know how to do to get hour, min and sec into ascii. I will not have them converted into numbers. My code: time_t tid; tm * ptm; time(&tid); ptm = gmtime(&tid); struct timeval *Tps; struct timezone *Tzp; Tps = (struct timeval* ) malloc(sizeof(struct timeval)); Tzp = 0; gettimeofday(Tps, Tzp); hour = ptm->tm_hour; //become integers, will have ascii min = ptm->tm_min; sec = ptm ->tm_sec; //Stefan

[Maxwell Chen]

Try sprintf(buffer, "%02d:%02d:%02d", hour, min, sec); Maxwell Chen

[styve]

yes, I can use it, but then there will be digits. I will have it in ascii format, because it take less space in a file.

[Maxwell Chen]

For saving space issue, I would use this way... Seven bytes for the whole date and time. unsigned char sDateTime[7] = { 20, 03, 2, 19, 16, 17, 55 }; int iYr, iMon, iDay, iHr, iMin, iSec; // To extract from buffer... iYr = sDateTime[0] * 100 + sDateTime[1]; iMon = sDateTime[2]; iDay = sDateTime[3]; iHr = sDateTime[4]; iMin = sDateTime[5]; iSec = sDateTime[6]; Maxwell Chen

[Prakash Nadar]

styve wrote: I will have it in ascii format, because it take less space in a file :confused::confused: Any ways if you want to store 'A' in the file what do you want to store 'A' or '65' (65 is ascii for 'A') which one takes more space ???

---

"When death smiles at you, only thing you can do is smile back at it" - Russel Crowe (Gladiator)

[styve]

Hi! Your solution were good. It made me think in another way. But there is one problem. How will I solve microseconds (6 digits)?? Two digits is one byte, so six digits willbe 3 byte??

[styve]

One letter or one digit that is stored to a file is one byte. If I only store A, the file is one byte. If I store 65, the file is two byte. It was that I meant

[David Crow]

styve wrote: If I store 65, the file is two byte. Not necessarily. Consider this:

FILE *f;
char letr = 'A';
fwrite(&letr, sizeof(char), 1, f);

letr = 65;
fwrite(&letr, sizeof(char), 1, f);

The size of the file in both cases will be one byte.

char *ltrs = "65";
fwrite(ltrs, sizeof(char), 2, f);

Now the size of the file will be two bytes.

int num = 65;
fwrite(&num, sizeof(int), 1, f);

Now the size of the file will be four bytes.

---

"The pointy end goes in the other man." - Antonio Banderas (Zorro, 1998)