strtol problem

[nss]

I am using strtol to catch bad entries: looping on i { fgets(line, MAX_SIZE -1, fp); pc = line; for ( unsigned int j = 0; j < cols ; ++j, ++col) { num = strtol( pc, &pc, 10); cout << i << " " << j << " " <<num<< " pc " << (*pc==' '?'.':*pc) << endl; line comes from a file that looks like: 9 a5 3 9 1 3 9 5 5 7 10 9 4 6 10 10 8 5 1 7 10 12 1 3 10 10 10 11 12 3 /// an 'a' snuck in...strtol should arrest it, but it never does. (however with a9 5 3 9 3 9 3 8 5 3, I see the letter 'a' in the cout.....) Here is the output for the first case (when a doesnt show...) 0 0 9 pc . 0 1 0 pc .//pc should have been 'a', num is 0 is okay since it didnt get read 0 2 0 pc .//'num' should have been 5 0 3 0 pc . 0 4 0 pc . 0 5 0 pc . 0 6 0 pc . 0 7 0 pc . 0 8 0 pc . 0 9 0 pc . Any ideas why strtol isnt performing as I understand it should? thanks, ns

[David Crow]

nss wrote: Any ideas why strtol isnt performing as I understand it should? What are you expecting it to do? When calling strtol("9 a5 3 9 1 3 9 5 5 7", ...), processing stops at the space following the first 9 because that is the first character that it did not recognize as part of the number. The same is true for calling strtol("a9 5 3 9 3 9 3 8 5 3", ...), in that processing stops at the 'a' because that is the first character that it did not recognize as part of the number. Had you used base 16 instead, processing would have stopped at the space following 'a9'. Make sense?

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"The pointy end goes in the other man." - Antonio Banderas (Zorro, 1998)

[nss]

right, the first arrest is at ' ', but right afterit should choke on 'a' as well...... 23 12 a4 56..... It never prints out *pc = 'a'