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C++ pointer question

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  • P patnsnaudy

    If I have a pointer to an object foo is there anyway to tell if that object actually exists? Say I only want one window open at a time.

    void
    foo::openWindow()
    {
       static foo* ptr = NULL;
       if (ptr)  
          ptr->closeWindow();
       ptr = this;
    
       // open this window 
       ...
    }
    

    So, the second time through this code I want to know if ptr is still valid, because it may have been deleted without my knowledge. I know there are other ways to do this, but I want to know if I can figure out if ptr still exists. I've tried adding a ptr = dynamic_cast<foo*>(ptr);, but this throws an exception if ptr has been deleted, and I'd rather not use a try block. Thanks in advance

    J Offline
    J Offline
    Joe Woodbury
    wrote on last edited by
    #2

    I completely fail to see the purpose of your code, but that aside, you can simply check whether the 'this' pointer is NULL. Anyone who thinks he has a better idea of what's good for people than people do is a swine. - P.J. O'Rourke

    P 1 Reply Last reply
    0
    • P patnsnaudy

      If I have a pointer to an object foo is there anyway to tell if that object actually exists? Say I only want one window open at a time.

      void
      foo::openWindow()
      {
         static foo* ptr = NULL;
         if (ptr)  
            ptr->closeWindow();
         ptr = this;
      
         // open this window 
         ...
      }
      

      So, the second time through this code I want to know if ptr is still valid, because it may have been deleted without my knowledge. I know there are other ways to do this, but I want to know if I can figure out if ptr still exists. I've tried adding a ptr = dynamic_cast<foo*>(ptr);, but this throws an exception if ptr has been deleted, and I'd rather not use a try block. Thanks in advance

      T Offline
      T Offline
      TFrancis
      wrote on last edited by
      #3

      If there's some function call out there that tells you if a spot in memory is valid that'd be a real easy way of doing this. But I don't know of one. My suggestion. Make ptr a static member of the foo class. Then, in your foo destructor, if ptr == this, set ptr = NULL. Tim

      P D 2 Replies Last reply
      0
      • T TFrancis

        If there's some function call out there that tells you if a spot in memory is valid that'd be a real easy way of doing this. But I don't know of one. My suggestion. Make ptr a static member of the foo class. Then, in your foo destructor, if ptr == this, set ptr = NULL. Tim

        P Offline
        P Offline
        patnsnaudy
        wrote on last edited by
        #4

        I know I can do this, but I did not want to add a member for this. Thanks though! Jerry

        1 Reply Last reply
        0
        • J Joe Woodbury

          I completely fail to see the purpose of your code, but that aside, you can simply check whether the 'this' pointer is NULL. Anyone who thinks he has a better idea of what's good for people than people do is a swine. - P.J. O'Rourke

          P Offline
          P Offline
          patnsnaudy
          wrote on last edited by
          #5

          Yeah but if you create

          foo *a = new foo();
          foo *b = new foo();
          
          a.openWindow();
          b.openWindow(); // This should close a.
          delete b;       // ptr in openWindow() still points 
                          //  to the space b used to occupy.
          a.openWindow(); // Trys to close b, but b no longer exists (ERROR).
          

          I know I could create a member and set it to this in openWindow and NULL in closeWindow, but I do not want to have a member for this. If you change the code to use a dynamic_cast and put a try-catch(...) around it this will work as is, but the powers that be don't like try-catch, so I'm not allowed to use it.

          C R 2 Replies Last reply
          0
          • P patnsnaudy

            Yeah but if you create

            foo *a = new foo();
            foo *b = new foo();
            
            a.openWindow();
            b.openWindow(); // This should close a.
            delete b;       // ptr in openWindow() still points 
                            //  to the space b used to occupy.
            a.openWindow(); // Trys to close b, but b no longer exists (ERROR).
            

            I know I could create a member and set it to this in openWindow and NULL in closeWindow, but I do not want to have a member for this. If you change the code to use a dynamic_cast and put a try-catch(...) around it this will work as is, but the powers that be don't like try-catch, so I'm not allowed to use it.

            C Offline
            C Offline
            Christian Graus
            wrote on last edited by
            #6

            patnsnaudy wrote: but the powers that be don't like try-catch, so I'm not allowed to use it. Not being allowed to use try..catch is wrong, but so is a design that throws exceptions based on bad coding, so on aggregate, I'm with the 'powers that be'. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder

            1 Reply Last reply
            0
            • P patnsnaudy

              If I have a pointer to an object foo is there anyway to tell if that object actually exists? Say I only want one window open at a time.

              void
              foo::openWindow()
              {
                 static foo* ptr = NULL;
                 if (ptr)  
                    ptr->closeWindow();
                 ptr = this;
              
                 // open this window 
                 ...
              }
              

              So, the second time through this code I want to know if ptr is still valid, because it may have been deleted without my knowledge. I know there are other ways to do this, but I want to know if I can figure out if ptr still exists. I've tried adding a ptr = dynamic_cast<foo*>(ptr);, but this throws an exception if ptr has been deleted, and I'd rather not use a try block. Thanks in advance

              C Offline
              C Offline
              Christian Graus
              wrote on last edited by
              #7

              Add an operator HWND to the class that returns the window handle and call ::IsWindow. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder

              P 1 Reply Last reply
              0
              • C Christian Graus

                Add an operator HWND to the class that returns the window handle and call ::IsWindow. Christian I have drunk the cool-aid and found it wan and bitter. - Chris Maunder

                P Offline
                P Offline
                patnsnaudy
                wrote on last edited by
                #8

                There is already a function to return HWND I think, if this is derived from the window class (I'll have to check tomorrow at work). ::IsWindow is a great suggestion! I was looking for a magical function that would look at a piece of memory and tell me if it had been deleted, but IsWindow should work. Thanks

                P 1 Reply Last reply
                0
                • P patnsnaudy

                  There is already a function to return HWND I think, if this is derived from the window class (I'll have to check tomorrow at work). ::IsWindow is a great suggestion! I was looking for a magical function that would look at a piece of memory and tell me if it had been deleted, but IsWindow should work. Thanks

                  P Offline
                  P Offline
                  Prakash Nadar
                  wrote on last edited by
                  #9

                  it will not work if the pointer to the dialog is deleteed.


                  MSN Messenger. prakashnadar@msn.com

                  P 1 Reply Last reply
                  0
                  • P patnsnaudy

                    If I have a pointer to an object foo is there anyway to tell if that object actually exists? Say I only want one window open at a time.

                    void
                    foo::openWindow()
                    {
                       static foo* ptr = NULL;
                       if (ptr)  
                          ptr->closeWindow();
                       ptr = this;
                    
                       // open this window 
                       ...
                    }
                    

                    So, the second time through this code I want to know if ptr is still valid, because it may have been deleted without my knowledge. I know there are other ways to do this, but I want to know if I can figure out if ptr still exists. I've tried adding a ptr = dynamic_cast<foo*>(ptr);, but this throws an exception if ptr has been deleted, and I'd rather not use a try block. Thanks in advance

                    R Offline
                    R Offline
                    Ryan Binns
                    wrote on last edited by
                    #10

                    To determine if a pointer points to readable memory, use the IsBadReadPtr() function. If it returns FALSE, then the pointer cannot be read. Hope this helps,

                    Ryan

                    "Punctuality is only a virtue for those who aren't smart enough to think of good excuses for being late" John Nichol "Point Of Impact"

                    1 Reply Last reply
                    0
                    • P patnsnaudy

                      Yeah but if you create

                      foo *a = new foo();
                      foo *b = new foo();
                      
                      a.openWindow();
                      b.openWindow(); // This should close a.
                      delete b;       // ptr in openWindow() still points 
                                      //  to the space b used to occupy.
                      a.openWindow(); // Trys to close b, but b no longer exists (ERROR).
                      

                      I know I could create a member and set it to this in openWindow and NULL in closeWindow, but I do not want to have a member for this. If you change the code to use a dynamic_cast and put a try-catch(...) around it this will work as is, but the powers that be don't like try-catch, so I'm not allowed to use it.

                      R Offline
                      R Offline
                      Ravi Bhavnani
                      wrote on last edited by
                      #11

                      It's good coding hygiene to set a deleted pointer to NULL. This will help prevent run-time errors and could make your code simpler. /ravi My new year's resolution: 2048 x 1536 Home | Articles | Freeware | Music ravib@ravib.com

                      1 Reply Last reply
                      0
                      • T TFrancis

                        If there's some function call out there that tells you if a spot in memory is valid that'd be a real easy way of doing this. But I don't know of one. My suggestion. Make ptr a static member of the foo class. Then, in your foo destructor, if ptr == this, set ptr = NULL. Tim

                        D Offline
                        D Offline
                        David Crow
                        wrote on last edited by
                        #12

                        TFrancis wrote: If there's some function call out there that tells you if a spot in memory is valid that'd be a real easy way of doing this. But I don't know of one. How about:

                        IsBadReadPtr()
                        IsBadCodePtr()
                        IsBadStringPtr()
                        IsBadWritePtr()


                        "The pointy end goes in the other man." - Antonio Banderas (Zorro, 1998)

                        1 Reply Last reply
                        0
                        • P Prakash Nadar

                          it will not work if the pointer to the dialog is deleteed.


                          MSN Messenger. prakashnadar@msn.com

                          P Offline
                          P Offline
                          patnsnaudy
                          wrote on last edited by
                          #13

                          By it will not work does that mean that it will crash if the pointer has been deleted?

                          P 1 Reply Last reply
                          0
                          • P patnsnaudy

                            By it will not work does that mean that it will crash if the pointer has been deleted?

                            P Offline
                            P Offline
                            Prakash Nadar
                            wrote on last edited by
                            #14

                            yes,it will very unpredictable, it may crash in some cases and it will work in some cases. but then working with deleted pointer is very bad idea.


                            MSN Messenger. prakashnadar@msn.com

                            1 Reply Last reply
                            0
                            • P patnsnaudy

                              If I have a pointer to an object foo is there anyway to tell if that object actually exists? Say I only want one window open at a time.

                              void
                              foo::openWindow()
                              {
                                 static foo* ptr = NULL;
                                 if (ptr)  
                                    ptr->closeWindow();
                                 ptr = this;
                              
                                 // open this window 
                                 ...
                              }
                              

                              So, the second time through this code I want to know if ptr is still valid, because it may have been deleted without my knowledge. I know there are other ways to do this, but I want to know if I can figure out if ptr still exists. I've tried adding a ptr = dynamic_cast<foo*>(ptr);, but this throws an exception if ptr has been deleted, and I'd rather not use a try block. Thanks in advance

                              P Offline
                              P Offline
                              patnsnaudy
                              wrote on last edited by
                              #15

                              I just created a static pointer to the window and set it to this in the openWindow function and NULL in the dtor. Thanks

                              1 Reply Last reply
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