sizeof operator

[rohit dhamija 0]

Dear All, The sizeof keyword gives the amount of storage, in bytes, associated with a variable or a type. Can any body suggest how to make our own function that operates like sizeof and gives the amount of storage in bytes. Regards, Rohit

[Michael Dunn]

Untested, but here's an idea:

template<typename T> size_t Sizeof()
{
T* p1 = (T*) 100, *p2 = p1+1;

return (BYTE*) p2 - (BYTE*) p1;
}

size_t n = Sizeof<int>();

--Mike-- Personal stuff:: Ericahist | Homepage Shareware stuff:: 1ClickPicGrabber | RightClick-Encrypt CP stuff:: CP SearchBar v2.0.2 | C++ Forum FAQ ---- Laugh it up, fuzzball.

[Jorgen Sigvardsson]

What's wrong with:

template <typename T> size_t Sizeof() {
return sizeof T;
}

For completeness I'd add

template <typename T> struct size_of : public std::generator<size_t> {
size_t operator()() {
return sizeof T;
}
};

and/or

template <typename T> struct size_of : public std::unary_function<size_t, T> {
size_t operator()(const T& v) {
return sizeof v;
}
};

-- Booohoo!

[Michael Dunn]

I thought the original question was how to make your own sizeof operator. If you use sizeof in your Sizeof() it doesn't count ;P --Mike-- Personal stuff:: Ericahist | Homepage Shareware stuff:: 1ClickPicGrabber | RightClick-Encrypt CP stuff:: CP SearchBar v2.0.2 | C++ Forum FAQ ---- You cannot truly appreciate Dilbert unless you've read it in the original Klingon.