convert float to int without rounding

[Dev578]

How would one convert a float to an int without rounding it? Currently: float f = 1.9; int i = (int)f; i would equal 2. How do I get it to not round, and have i equal 1 in the above example? Any help is appreciated. -Dev578

[Tim Smith]

As defined by the C++ standard, floating to integer conversions truncate. So 1.9 would convert to 1. Tim Smith I'm going to patent thought. I have yet to see any prior art.

[PJ Arends]

int i = (int)(f + 0.5);

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](http://www.canucks.com)Sonork 100.11743 Chicken Little "You're obviously a superstar." - Christian Graus about me - 12 Feb '03 Within you lies the power for good - Use it!

[Gary R Wheeler]

You expression rounds, which I think is the opposite of what he wants, which is simple truncation.

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Software Zen: delete this;

[Gary R Wheeler]

i would not equal 2. Simple 'C'-style casts truncate, so you will see i == 1.

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Software Zen: delete this;