#define style templates and float

[J B 0]

Hi guys, I tried to compile and run a #define type templates example code in Visual C++:

#include 

#define define_max(type)	\
	type max(type d1, type d2) { \
		if (d1 > d2)	\
			return (d1); \
		return (d2);	\
	}

define_max(int);
define_max(float);
define_max(char);

int main(void)
{
	int i = max(100, 800);
	char ch = max('A', 'Q');
	float f = max(3.5, 8.7);

	return 0;
}

and I am getting compile error ambiguous call to overloaded function on the line

float f = max(3.5, 8.7);

If I replace float with double, it will compile and run ok. Does anyone know why that is? Is there some kind of limitation on uses of float in Visual C++? Thanks alot

[David Crow]

This is just a guess, but try replacing the four occurrences of max() with something like max1().

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"When I was born I was so surprised that I didn't talk for a year and a half." - Gracie Allen

[vcplusplus]

3.5 and 8.7 are consider constant doubles. When I compile the code below, VC gives me a warning for "a" but not for "b"float a = 2.4; warning C4305: 'initializing' : truncation from 'const double' to 'float' float b = 2.4f;

[J B 0]

vcplusplus wrote: float a = 2.4;warning C4305: 'initializing' : truncation from 'const double' to 'float'float b = 2.4f; It makes a difference. I suppose the appended f tells the compiler to treat the numbers as float type? Thanks.