#define syntax for create a class instance

[hyling]

Hi, Is it possible to create a macro that would create an instance of a class? I'm trying this but the compiler won't accept it: #define Logger() (MyLogger tempLogger(__FUNCTION__, __FILE__, __LINE__)) Thanks Hua-Ying

[toxcct]

and what does the compiler say ?

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[toxcct][VisualCalc]

[Neagoe Gabriel]

class MyLogger { MyLogger( char*, char*, char*) { } }; #define Logger() (MyLogger tempLogger(__FUNCTION__, __FILE__, __LINE__)) no error on visual c++ 6.0... NG

[hyling]

error C2059: syntax error : ')' error C2146: syntax error : missing ')' before identifier 'tempLogger' error C3861: 'tempLogger': identifier not found, even with argument-dependent lookup

[hyling]

The syntax error only occurs when I try to use the macro. The errors are: error C2059: syntax error : ')' error C2146: syntax error : missing ')' before identifier 'tempLogger' error C3861: 'tempLogger': identifier not found, even with argument-dependent lookup Hua-Ying

[Anonymous]

#include using namespace std; #define Logger() MyLogger tempLogger(__FUNCTION__, __FILE__, __LINE__) class MyLogger { public: MyLogger(char *pFunction, char *pFile, long Line) { cout<

[hyling]

Thanks that really does work! I've always though that argument in a #define were separated by spaces so that it would see 3 arguments there. I guess I was wrong!