open file dialog

[Anonymous]

i want to implement something like onFileopen() i have a button, which when clicked should help me to browse to get the path of an executable on the system. onFileopen() should work but its ging error saying its a protected member and cannot be accessed please suggest a solution thanks r.k

[Christian Graus]

The MFC source code is on your hard drive, so you can look at the file dialog code you're wanting to run and use it as a guide to impliment your own code. Just do a search for files containing the method name in the appropriate folder, or if you don't know it, on the base folder of your SDK or VC++ install. Christian Graus - Microsoft MVP - C++

[MaxVampire82]

explicit CFileDialog( BOOL bOpenFileDialog, LPCTSTR lpszDefExt = NULL, LPCTSTR lpszFileName = NULL, DWORD dwFlags = OFN_HIDEREADONLY | OFN_OVERWRITEPROMPT, LPCTSTR lpszFilter = NULL, CWnd* pParentWnd = NULL, DWORD dwSize = 0 ); You'd better search the MSDN.

[David Crow]

Anonymous wrote: onFileopen() should work but its ging error saying its a protected member and cannot be accessed Show us the code snippet that the compiler is complaining about.

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