is there a reverse of @"abc"?

[Ariadne]

Hi if I read command line args I get results of @"line\nline2" how can I convert this into "line1\nline2"? In other words: how to remove the '@'? Ariadne

[leppie]

They are the same thing, the @ only defines different escaping routines. :) xacc-ide 0.0.15 now with C#, MSIL, C, XML, ASP.NET, Nemerle, MyXaml and HLSL coloring - Screenshots

[Ariadne]

leppie wrote: They are the same thing, the @ only defines different escaping routines. ok, but how can I change the escaping routine. if I do: sPrompt=args[i] and args[i] contains a '\' the real string of sPrompt is something like: @"...\...", but I want show this prompt in MessagBox without this '@' escape function. ie. I want show more than one line, if I get in args[i] a '\n' thanks! Ariadne

[leppie]

You will need to do a str.Replace(@"\n","\n") :-> xacc-ide 0.0.15 now with C#, MSIL, C, XML, ASP.NET, Nemerle, MyXaml and HLSL coloring - Screenshots

[Luis Alonso Ramos]

The escaping routine is for the compiler, and not for the string itself. If you do Console.WriteLine("line1\\nline2") or Console.WriteLine(@"line1\nline2"), you'll get the same output:

line1\nline2

In the first case, to insert a backslash in the string, you need to double it (otherwise it will be interpreted as a special character: eg. \n as newline). In the second example, the @ means that a different escaping will be performed (most special characters won't be escaped) so \n produces exactly that, \n. The @ makes a difference when specifying paths in code:

string path1 = "C:\\Program Files\\Microsoft";
string path2 = @"C:\Program Files\Microsoft";

In memory, both path1 and path2 will contain exactly the same. If you read the string from anywhere typed by the user, you don't have to worry about escape characters. If he types one backslash, you'll get it. Escaping is only when specifying strings in code. -- LuisR

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Luis Alonso Ramos Intelectix - Chihuahua, Mexico Not much here: My CP Blog!

The amount of sleep the average person needs is five more minutes. -- Vikram A Punathambekar, Aug. 11, 2005

[Ariadne]

Luis Alonso Ramos wrote: The escaping routine is for the compiler, and not for the string itself. no, I think not, because I get the '@'-problem at runtime. but I'm happy leppie solved the problem with

sPrompt=sPrompt.Replace(@"\n","\n");

It works! :) Thanks leppie Ariadne

[Luis Alonso Ramos]

What that particular line of code is doing is replacing the characters \n (backslash followed by an n) with an actual newline character. It is the exact equivalent of: sPrompt = sPrompt.Replace("\\n", "\n"). Somehow you read the sPrompt string from somewhere that doesn't support escaping of characters (a resource maybe?) so you ended up with the characters '\' and 'n' in memory, instead of the actual newline (char 13) character. But the escaping only works when specifying strings by code, and it's performed by the compiler. -- LuisR

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Luis Alonso Ramos Intelectix - Chihuahua, Mexico Not much here: My CP Blog!

The amount of sleep the average person needs is five more minutes. -- Vikram A Punathambekar, Aug. 11, 2005