Problem with XPathNavigator

[RoadieGS]

I am attempting to extract some data from the xml below with the following code: XPathDocument xmlDoc = new XPathDocument(URL that I supply); XPathNavigator nav = xmlDoc.CreateNavigator(); nav.Select("/ISBNdb/BookList/BookData/AuthorsText"); Console.WriteLine(nav.Value); The problem is the value returned is all of the elements concatenated together: Applied Microsoft. NET framework programming in Microsoft Visual Basic. NETJeffrey Richter, Francesco BalenaRedmond, Wash. : Microsoft Press, c2003. I have tried everthing and have no idea why I am getting this behavior. Any help would be greatly appreciated. Thanks. Gary This is the xml that is loaded into the XPathDocument: Applied Microsoft. NET framework programming in Microsoft Visual Basic. NET Jeffrey Richter, Francesco Balena Redmond, Wash. : Microsoft Press, c2003. -- modified at 10:50 Friday 5th May, 2006

[Josh Smith]

You should use the XPathNodeIterator which is returned from the Select method, not the Value of the navigator.

private void Form1_Load(object sender, System.EventArgs e)
{
XPathDocument xmlDoc = new XPathDocument("..\\..\\data.xml");
XPathNavigator nav = xmlDoc.CreateNavigator();
XPathNodeIterator iter = nav.Select("/ISBNdb/BookList/BookData/AuthorsText");
while( iter.MoveNext() )
Console.WriteLine(iter.Current.Value);
}

Josh

[RoadieGS]

I tried that as well. I got the same exact result. Did it work correctly for you?

[Josh Smith]

Yes

[RoadieGS]

VS 2003 or VS 2005? I am using 2003. Any thoughts on why it would work for you and not me? Thanks!

[Josh Smith]

2003. I don't know what the difference could be. I posted the exact code that worked for me, so it must be an Act of God. :doh: Josh

[RoadieGS]

I enjoyed the sense of humor.

[George L Jackson]

I tried Josh's code in 1.1 and it worked as advertised!