real simple question - decimals

[Sam 2006]

hey all, i have a really simple question, im amazed i cant find out how to do this. i have 2 integers, called x and y. i need to show printf("%d", (x/y)); everything i try will round it to the closest integer. i've tried using double for x,y, another variable that stores the value of x/y, but it still rounds the to the closest integer. how can i display a number not rounded to the closest integer? thanks in advance

[Michael Dunn]

You also need to change %d to %lf to tell printf() that it should output a double, not an int.

--Mike-- Visual C++ MVP :cool: LINKS~! Ericahist | PimpFish | CP SearchBar v3.0 | C++ Forum FAQ

[bob16972]

Don't forget to make sure at least one of the components in the expression is a float or a double to avoid truncations. If both x and y are int's you will notice a truncation of the result before the printf formatting occurs. printf("%f\n",(double)x/y);

[Hamid Taebi]

See double c; double x = 123.456; double y = 2.1; c=x/y; printf( "%f\n", c);//output->58.788571_**

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whitesky

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[bob16972]

If both of the numbers are of type int like they stated then you'll get (On Visual C++ 6.0 and VC++ 2003) #include "stdafx.h" int main(int argc, char* argv[]) { int x=1; int y=9; printf("%f\n",x/y); // The expression gets truncated before formatting printf("%lf\n",x/y); // The expression gets truncated before formatting printf("%f\n",(double)x/y); // The correct way when both are integers printf("%lf\n",(double)x/y); // The correct way when both are integers return 0; } *************** OUTPUT VC++ 6.0******************* -1.#QNAN0 -1.#QNAN0 0.111111 0.111111 Press any key to continue *************** OUTPUT VC++ 6.0******************* 796482944349676280000000000000000000000000000000000 000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000 000000000000000000000000000000.000000 796482944349676280000000000000000000000000000000000 000000000000000000000000000000000000000000000000000 000000000000000000000000000000000000000000000000000 000000000000000000000000000000.000000 0.111111 0.111111 Press any key to continue

[Sam 2006]

that worked thanks!

[Gary R Wheeler]

One slight correction: Use the "%f" format code for values of type float, and "%lf" format code for values of type double.

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