Heap corruption?!
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Hello Looks like my C++ is getting really rusty. While playing a bit in a console project the following code gave me a strange heap corruption error.
#include
using namespace std;
void main()
{
char* MyText = new char;
cin>>MyText;
delete[] MyText;
}It's not even an exception. Sometimes it says "Windows have set a breakpoint in your application because of a heap error." And a break point appears somewhere in the iostream file. Other times, an ugly error message appears saying "HEAP CORRUPTION DETECTED after a normal block. CRT detected that application wrote to memory after end of heap buffer.", Any clue??
Regards:rose:
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Hello Looks like my C++ is getting really rusty. While playing a bit in a console project the following code gave me a strange heap corruption error.
#include
using namespace std;
void main()
{
char* MyText = new char;
cin>>MyText;
delete[] MyText;
}It's not even an exception. Sometimes it says "Windows have set a breakpoint in your application because of a heap error." And a break point appears somewhere in the iostream file. Other times, an ugly error message appears saying "HEAP CORRUPTION DETECTED after a normal block. CRT detected that application wrote to memory after end of heap buffer.", Any clue??
Regards:rose:
Nader Elshehabi wrote:
char* MyText = new char; cin>>MyText; delete[] MyText;
newmatches up withdelete.new[]matches up withdelete[]. Callingdelete[]on something that wasnew'd will result in a heap corruption. To fix the problem:void main() { char* MyText = new char; cin>>MyText; delete MyText; }or
void main() { char* MyText = new char[100]; cin>>MyText; delete [] MyText; }If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
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Hello Looks like my C++ is getting really rusty. While playing a bit in a console project the following code gave me a strange heap corruption error.
#include
using namespace std;
void main()
{
char* MyText = new char;
cin>>MyText;
delete[] MyText;
}It's not even an exception. Sometimes it says "Windows have set a breakpoint in your application because of a heap error." And a break point appears somewhere in the iostream file. Other times, an ugly error message appears saying "HEAP CORRUPTION DETECTED after a normal block. CRT detected that application wrote to memory after end of heap buffer.", Any clue??
Regards:rose:
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Nader Elshehabi wrote:
char* MyText = new char; cin>>MyText; delete[] MyText;
newmatches up withdelete.new[]matches up withdelete[]. Callingdelete[]on something that wasnew'd will result in a heap corruption. To fix the problem:void main() { char* MyText = new char; cin>>MyText; delete MyText; }or
void main() { char* MyText = new char[100]; cin>>MyText; delete [] MyText; }If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
Hello Thanks for replying. Well, the first coder didn't work, while the second did. Yet, that makes a buffer of N chars. That's not what I want. What if the user inputs n+1 chars. I tried it and it made the same heap corruption error. Also what if I dynamically reallocate my array -or pointer-?? If you got more details or point me to some article about this issue, I'd be grateful. Thanks again.
Regards:rose:
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Beside what Zac said, another suspicious area is cin>>MyText; When you expected MyText is one char, your input could easily be more than one char, which would cause a memory problem.
Best, Jun
Hello Jun. Actually my input field is
char*, and I was expecting a text rather than just one char. Besides, this is nothing more than an experimental project which turned out to be disastrous!!;PRegards:rose:
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Hello Thanks for replying. Well, the first coder didn't work, while the second did. Yet, that makes a buffer of N chars. That's not what I want. What if the user inputs n+1 chars. I tried it and it made the same heap corruption error. Also what if I dynamically reallocate my array -or pointer-?? If you got more details or point me to some article about this issue, I'd be grateful. Thanks again.
Regards:rose:
Nader Elshehabi wrote:
Well, the first coder didn't work, while the second did.
The first code has another problem due to the fact that cin's operator>> will pull in 2 characters even if you only typed 1 (the character you typed and a '\0' to terminate the string). If you are only trying to pull in 1 character, the cin.getc() would work better.
Nader Elshehabi wrote:
Yet, that makes a buffer of N chars. That's not what I want. What if the user inputs n+1 chars.
You will not be able to use the operator>> to do this (at least not yet ... as I said, the new proposal for the C++ standard has all overloaded operators that deal with char* now also overloaded for string). What you can do is iterate through it:
char ch; string input; while ((ch = cin.getc()) != '\n') { input += ch; }That will prevent any possibility of a buffer overflow issue, but will also be VERY slow (in comparison to pulling down a whole set of data at once).
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
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Nader Elshehabi wrote:
Well, the first coder didn't work, while the second did.
The first code has another problem due to the fact that cin's operator>> will pull in 2 characters even if you only typed 1 (the character you typed and a '\0' to terminate the string). If you are only trying to pull in 1 character, the cin.getc() would work better.
Nader Elshehabi wrote:
Yet, that makes a buffer of N chars. That's not what I want. What if the user inputs n+1 chars.
You will not be able to use the operator>> to do this (at least not yet ... as I said, the new proposal for the C++ standard has all overloaded operators that deal with char* now also overloaded for string). What you can do is iterate through it:
char ch; string input; while ((ch = cin.getc()) != '\n') { input += ch; }That will prevent any possibility of a buffer overflow issue, but will also be VERY slow (in comparison to pulling down a whole set of data at once).
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
Hello Thanks again for your reply! I got two more questions:-D. Take a look at this code;
char* MyText = new char[5];
cin>>MyText;
MyText = new char[10];
delete[] MyText;Now , I called a second
newwithout deleting the first one. Is there a leak here?? What if I didn't call a delete at all!! Once my program finishes and closes. Will the memory be freed? Or will it be permanently locked until reboot?Regards:rose:
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Hello Thanks again for your reply! I got two more questions:-D. Take a look at this code;
char* MyText = new char[5];
cin>>MyText;
MyText = new char[10];
delete[] MyText;Now , I called a second
newwithout deleting the first one. Is there a leak here?? What if I didn't call a delete at all!! Once my program finishes and closes. Will the memory be freed? Or will it be permanently locked until reboot?Regards:rose:
Nader Elshehabi wrote:
Is there a leak here??
Yes.
Nader Elshehabi wrote:
Will the memory be freed?
Yes.
"Talent without discipline is like an octopus on roller skates. There's plenty of movement, but you never know if it's going to be forward, backwards, or sideways." - H. Jackson Brown, Jr.
"Judge not by the eye but by the heart." - Native American Proverb
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Hello Thanks again for your reply! I got two more questions:-D. Take a look at this code;
char* MyText = new char[5];
cin>>MyText;
MyText = new char[10];
delete[] MyText;Now , I called a second
newwithout deleting the first one. Is there a leak here?? What if I didn't call a delete at all!! Once my program finishes and closes. Will the memory be freed? Or will it be permanently locked until reboot?Regards:rose:
Nader Elshehabi wrote:
Now , I called a second new without deleting the first one. Is there a leak here??
Are you coming from a Java/C# background by chance? Yes, this will result in a memory leak. Whenever you use new, you must have a delete call to match it. Having 2 calls to new and only 1 call to delete means here is a leak.
Nader Elshehabi wrote:
What if I didn't call a delete at all!! Once my program finishes and closes. Will the memory be freed? Or will it be permanently locked until reboot?
When the program exits its memory will be freed. You do NOT want to rely on this, though. Always clean up your memory properly.
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
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Nader Elshehabi wrote:
Is there a leak here??
Yes.
Nader Elshehabi wrote:
Will the memory be freed?
Yes.
"Talent without discipline is like an octopus on roller skates. There's plenty of movement, but you never know if it's going to be forward, backwards, or sideways." - H. Jackson Brown, Jr.
"Judge not by the eye but by the heart." - Native American Proverb
Hello Short, and straight answers!! Thanks:-D
Regards:rose:
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Nader Elshehabi wrote:
Now , I called a second new without deleting the first one. Is there a leak here??
Are you coming from a Java/C# background by chance? Yes, this will result in a memory leak. Whenever you use new, you must have a delete call to match it. Having 2 calls to new and only 1 call to delete means here is a leak.
Nader Elshehabi wrote:
What if I didn't call a delete at all!! Once my program finishes and closes. Will the memory be freed? Or will it be permanently locked until reboot?
When the program exits its memory will be freed. You do NOT want to rely on this, though. Always clean up your memory properly.
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
Hello
Zac Howland wrote:
Are you coming from a Java/C# background by chance?
Well, somehow:)! I was a good old timer C++ programmer:((. But last time I ever wrote C++ code was more than 3 years ago. So I got really rusty, coming back these days to C++ as a new comer. So, while refreshing all that good ol' C++ of mine, it's nice to have you guys around;) Thanks again.
Extra Regards:rose:
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Hello Looks like my C++ is getting really rusty. While playing a bit in a console project the following code gave me a strange heap corruption error.
#include
using namespace std;
void main()
{
char* MyText = new char;
cin>>MyText;
delete[] MyText;
}It's not even an exception. Sometimes it says "Windows have set a breakpoint in your application because of a heap error." And a break point appears somewhere in the iostream file. Other times, an ugly error message appears saying "HEAP CORRUPTION DETECTED after a normal block. CRT detected that application wrote to memory after end of heap buffer.", Any clue??
Regards:rose:
Try this instead.
#include <iostream> #include <iomanip> int main(int argc, char *argv[]) { using namespace std; char *pChar = new char[2]; cin >> setw(2) >> pChar; delete [] pChar; return 0; }You're reading too many charcters: you've got room for a NULL terminator (a string of zero length!) but your reading more and getting a buffer overrun. My code tells the IO classes how big the buffer is so it will not overrun it. If you only want to read a single char you could try doing this (in your code):cin >> *MyText;Steve
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Nader Elshehabi wrote:
Well, the first coder didn't work, while the second did.
The first code has another problem due to the fact that cin's operator>> will pull in 2 characters even if you only typed 1 (the character you typed and a '\0' to terminate the string). If you are only trying to pull in 1 character, the cin.getc() would work better.
Nader Elshehabi wrote:
Yet, that makes a buffer of N chars. That's not what I want. What if the user inputs n+1 chars.
You will not be able to use the operator>> to do this (at least not yet ... as I said, the new proposal for the C++ standard has all overloaded operators that deal with char* now also overloaded for string). What you can do is iterate through it:
char ch; string input; while ((ch = cin.getc()) != '\n') { input += ch; }That will prevent any possibility of a buffer overflow issue, but will also be VERY slow (in comparison to pulling down a whole set of data at once).
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
That's code is a good the way to read a single line, try this instead:
getline(cin, input);Steve
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That's code is a good the way to read a single line, try this instead:
getline(cin, input);Steve
That still has the problem that he will need to limit his buffer size in order to prevent overrun problems. And the safer version is:
char buffer[100] = {0}; cin.getline(buffer, 99);If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
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That still has the problem that he will need to limit his buffer size in order to prevent overrun problems. And the safer version is:
char buffer[100] = {0}; cin.getline(buffer, 99);If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
You don't have to limit the size of the buffer, you use
std::string. ie.string line; getline(cin, line);Assumesusing namespace std;and#include <iostream>and finally#include <string>Steve
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You don't have to limit the size of the buffer, you use
std::string. ie.string line; getline(cin, line);Assumesusing namespace std;and#include <iostream>and finally#include <string>Steve
Ah, you are correct. I completely forgot about the general getline function ... :doh:
If you decide to become a software engineer, you are signing up to have a 1/2" piece of silicon tell you exactly how stupid you really are for 8 hours a day, 5 days a week Zac
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Try this instead.
#include <iostream> #include <iomanip> int main(int argc, char *argv[]) { using namespace std; char *pChar = new char[2]; cin >> setw(2) >> pChar; delete [] pChar; return 0; }You're reading too many charcters: you've got room for a NULL terminator (a string of zero length!) but your reading more and getting a buffer overrun. My code tells the IO classes how big the buffer is so it will not overrun it. If you only want to read a single char you could try doing this (in your code):cin >> *MyText;Steve
Thanks Steve! I appreciate your response.:)
Regards:rose: