using return statement in "conditional operator (? :) "ternary operator

[Mushtaque Nizamani]

Hi, can we use return statement in "?:" conditional ternay operator. I am using like this (avar == 2)?return:executesomethng(..); but the compiler is not allowing me do that, and it gives the error C2059(syntax error : 'token'). Regards, Mushq

[Roger Stoltz]

Either way, in my opinion you're putting a lot of time and effort to write code that is hard to read and understand, even for yourself if you return to it two months from now. My suggestion is that you rewrite it: use an ordinary if-statement.

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"It's supposed to be hard, otherwise anybody could do it!" - selfquote

[Christian Graus]

A well written method would have only one return point.  The way to do this is, if (avar != 2) {     executesomething(..); }

Christian Graus - C++ MVP 'Why don't we jump on a fad that hasn't already been widely discredited ?' - Dilbert

[Bill Gates Antimatter Particle]

(avar == 2)?return:executesomethng(..); err am i missing something here or should this be: (avar == 2) ? return executesomethng(); : return executesomethngelse(); :|

"Life begins at 140"

[krmed]

Actually, I agree that there should be just one return, and the correct syntax for what you're trying would be

return (avar == 2) ? executesomething() : executesomethingelse();

Hope that helps.

Karl - WK5M PP-ASEL-IA (N43CS) PGP Key: 0xDB02E193 PGP Key Fingerprint: 8F06 5A2E 2735 892B 821C 871A 0411 94EA DB02 E193