Array Shift Register
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I've got a very large array of picture boxes that I'm trying to shift with out using a loop. I've tried looping through the array from last element to first, setting the prior element to the current element, however this takes too long. Basically I want to take the properties from elements [0] to [array length - 1] and set them to elements [1] to [array length]. And then take element [0] and update it programically. I'm trying to use the Array.CopyTo function, where I copy to a temp array but haven't had any success. Can anyone help!?!?
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I've got a very large array of picture boxes that I'm trying to shift with out using a loop. I've tried looping through the array from last element to first, setting the prior element to the current element, however this takes too long. Basically I want to take the properties from elements [0] to [array length - 1] and set them to elements [1] to [array length]. And then take element [0] and update it programically. I'm trying to use the Array.CopyTo function, where I copy to a temp array but haven't had any success. Can anyone help!?!?
I don't see how looping through the array could be taking too long? Do you have several million items in the array, or what? Besides, whatever method you try to use instead of a loop will still be using a loop in the end. You will only be wasting resources trying to avoid the inevitable. Could you show some of your code? That might give a clue to what the problem is.
--- single minded; short sighted; long gone;
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I don't see how looping through the array could be taking too long? Do you have several million items in the array, or what? Besides, whatever method you try to use instead of a loop will still be using a loop in the end. You will only be wasting resources trying to avoid the inevitable. Could you show some of your code? That might give a clue to what the problem is.
--- single minded; short sighted; long gone;
Here's the sample code for what I'm trying to do. I actually have a 2D array. It's an array of pictureBox arrays. If you picture it like a grid with rows and columns. I want to foreach row, I want to shift each column back one, and set the first element to a new image. Here's the code (two for loops) // Shift the lane to the right // // Loop through each array (row) // for(int i = 0; i < allLanes.Length; i++) { // Loop through each element in the array (column) // // From back to front // for(int j = allLanes[i].Length-1; j > 0; j--) { // If the previous element's image is the failed image // if(allLanes[i][j-1].Image == failImg) { // Set the previous element to a pass image // allLanes[i][j-1].Image = passImg; // Set the current elemtn to a fail image // allLanes[i][j].Image = failImg; } else { // Set the current element to a pass image // allLanes[i][j].Image = passImg; } // Thread.Sleep(1); // } Note the Thread.Sleep(1). If I remove this, the code start to bomb out saying either: System.Drawing element is in use elsewhere or sometimes the display simply doesn't finish updating with only some of the rows showing the shift.
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Here's the sample code for what I'm trying to do. I actually have a 2D array. It's an array of pictureBox arrays. If you picture it like a grid with rows and columns. I want to foreach row, I want to shift each column back one, and set the first element to a new image. Here's the code (two for loops) // Shift the lane to the right // // Loop through each array (row) // for(int i = 0; i < allLanes.Length; i++) { // Loop through each element in the array (column) // // From back to front // for(int j = allLanes[i].Length-1; j > 0; j--) { // If the previous element's image is the failed image // if(allLanes[i][j-1].Image == failImg) { // Set the previous element to a pass image // allLanes[i][j-1].Image = passImg; // Set the current elemtn to a fail image // allLanes[i][j].Image = failImg; } else { // Set the current element to a pass image // allLanes[i][j].Image = passImg; } // Thread.Sleep(1); // } Note the Thread.Sleep(1). If I remove this, the code start to bomb out saying either: System.Drawing element is in use elsewhere or sometimes the display simply doesn't finish updating with only some of the rows showing the shift.