Parameter not valid

[Viral Upadhyay]

HI, I am fecthing varbinary data from data base and converting it to Image data. i got error of 'Parameter is not valid' i use this code System.Drawing.Image img; byte[] photobyte = (byte[])dtPhoto.Rows[0][0]; using (MemoryStream stream = new MemoryStream((byte[])dtPhoto.Rows[0][0])) { img = System.Drawing.Image.FromStream(stream); // here i gor error img.Save(Response.OutputStream, System.Drawing.Imaging.ImageFormat.Jpeg); } Thanks

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[kubben]

Why are you using Response.OutputStream instead of the stream var you just created? Ben

[Viral Upadhyay]

Hi ben i use Response.OutputStream for display image on Page. thanks for reply...

Viral YahooID : just_viral My Site : www.theseoworld.info

[Guffa]

Are you trying to change the file format of the image, or why are you loading and saving the image? If you just want to send the image to the browser, don't use any Image object, just send the bytes.

--- single minded; short sighted; long gone;

[Viral Upadhyay]

Well i try it too but dont work can please tell me how to send the byte?? thanks for your reply..

Viral YahooID : just_viral My Site : www.theseoworld.info

[Guffa]

Use the Response.BinaryWrite method.

--- single minded; short sighted; long gone;