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  4. Using IXMLHTTPRequest->send( ... ) on Vista

Using IXMLHTTPRequest->send( ... ) on Vista

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  • A Offline
    A Offline
    Andy H
    wrote on last edited by
    #1

    Has anyone come accross this issue on Vista? I have a program that uses: hr = IXMLHTTPRequest->send( ... ); which FAILS only on Vista. Any idea why? Works fine on XP with which we develop.

    J 1 Reply Last reply
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    • A Andy H

      Has anyone come accross this issue on Vista? I have a program that uses: hr = IXMLHTTPRequest->send( ... ); which FAILS only on Vista. Any idea why? Works fine on XP with which we develop.

      J Offline
      J Offline
      Jonathan Darka
      wrote on last edited by
      #2

      What's the value of hr ?


      Jonathan Wilkes Darka[Xanya.net]

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      • J Jonathan Darka

        What's the value of hr ?


        Jonathan Wilkes Darka[Xanya.net]

        A Offline
        A Offline
        Andy H
        wrote on last edited by
        #3

        I don't know as the Vista PC is not a development PC. I will have to investigate that when I can. Just wondered if someone had already crossed this bridge. It's probably due to Vista's tighter security policy (not UAC), and probably have to use a different class instead of IXMLHTTPRequest. So if anyone knows the answer I would be interested to here from you.

        J 1 Reply Last reply
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        • A Andy H

          I don't know as the Vista PC is not a development PC. I will have to investigate that when I can. Just wondered if someone had already crossed this bridge. It's probably due to Vista's tighter security policy (not UAC), and probably have to use a different class instead of IXMLHTTPRequest. So if anyone knows the answer I would be interested to here from you.

          J Offline
          J Offline
          Jonathan Darka
          wrote on last edited by
          #4

          You could output the value of the hr using OutputDebugString() and then use DebugView from sys internals to see the value on the vista machine.


          Jonathan Wilkes Darka[Xanya.net]

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