Runtime Creation Of Button+Adding Events+Sourabh
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Thanks, its working now.. I have one more problem, in the page load i have written this
Dim txtname As TextBox txtname = New TextBox txtname.AutoPostBack = False txtname.BackColor = Drawing.Color.AliceBlue txtname.BorderColor = Drawing.Color.Black nameHolder.Controls.Add(txtname)but in the event: Public Sub btnhandler_click(ByVal sender As Object, ByVal e As EventArgs) ' when i type "txtn" and try for intelisence, it dosent show the control. End Sub RegardsThanks and Regards,
The variable
txtnamehas been defined locally in another procedure. It doesn't have scope in your event handler procedure so it won't appear in intellisense. To get a reference to the TextBox control that has raised the event, you need to callFindControlon the control that contains the TextBoxes. You should define some naming convention for each TextBox you dynamically create so that you have a means of obtaining a reference to each one by name.Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
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The variable
txtnamehas been defined locally in another procedure. It doesn't have scope in your event handler procedure so it won't appear in intellisense. To get a reference to the TextBox control that has raised the event, you need to callFindControlon the control that contains the TextBoxes. You should define some naming convention for each TextBox you dynamically create so that you have a means of obtaining a reference to each one by name.Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
I am doing it like this: but its wrong. I didt understand what you wanted to say, please correct me. dssave.Tables("dtUsers").Rows(0)("UserName") = nameHolder.FindControl(txtname.Text.Trim) it gives an error. Object reference not set to an instance of an object.
Thanks and Regards,
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I am doing it like this: but its wrong. I didt understand what you wanted to say, please correct me. dssave.Tables("dtUsers").Rows(0)("UserName") = nameHolder.FindControl(txtname.Text.Trim) it gives an error. Object reference not set to an instance of an object.
Thanks and Regards,
Dot Net Jantu wrote:
ssave.Tables("dtUsers").Rows(0)("UserName") = nameHolder.FindControl(txtname.Text.Trim) it gives an error. Object reference not set to an instance of an object.
Yes, it will. To know why, you need to read the MSDN documentation to understand how the
FindControlmethod works. Have you done this?Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
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Dot Net Jantu wrote:
ssave.Tables("dtUsers").Rows(0)("UserName") = nameHolder.FindControl(txtname.Text.Trim) it gives an error. Object reference not set to an instance of an object.
Yes, it will. To know why, you need to read the MSDN documentation to understand how the
FindControlmethod works. Have you done this?Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
as per the msdn documentation, I have done this.. Dim name As TextBox = nameHolder.FindControl("txtname") also I had done this If (Not name Is Nothing) Then ' Get name's parent. Dim myControl2 As Control = name.Parent Response.Write("Parent of the text box is : " & myControl2.ID) Else Response.Write("Control not found.....") End If and its showing as control not found..
Thanks and Regards,
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as per the msdn documentation, I have done this.. Dim name As TextBox = nameHolder.FindControl("txtname") also I had done this If (Not name Is Nothing) Then ' Get name's parent. Dim myControl2 As Control = name.Parent Response.Write("Parent of the text box is : " & myControl2.ID) Else Response.Write("Control not found.....") End If and its showing as control not found..
Thanks and Regards,
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Dot Net Jantu wrote:
and its showing as control not found..
Have you actually added a control to the Controls collection of nameHolder with the ID 'txtname'?
Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
if this is what you mean then yes. Dim txtname As TextBox txtname = New TextBox txtname.AutoPostBack = False txtname.BackColor = Drawing.Color.AliceBlue txtname.BorderColor = Drawing.Color.Black nameHolder.Controls.Add(txtname)
Thanks and Regards,
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if this is what you mean then yes. Dim txtname As TextBox txtname = New TextBox txtname.AutoPostBack = False txtname.BackColor = Drawing.Color.AliceBlue txtname.BorderColor = Drawing.Color.Black nameHolder.Controls.Add(txtname)
Thanks and Regards,
Dot Net Jantu wrote:
Dim txtname As TextBox txtname = New TextBox txtname.AutoPostBack = False txtname.BackColor = Drawing.Color.AliceBlue txtname.BorderColor = Drawing.Color.Black nameHolder.Controls.Add(txtname)
The description of the
Control.FindControlwhich you said you had read, is as follows: Searches the current naming container for a server control with the specified id parameter. You haven't set theIDproperty for your control. The fact that you have declared a variable calledtxtnameand set it with a reference to your dynamically createdTextBoxobject is not relevent.Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
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Hi All, I have created a button at runtime on form load:
Dim btnSave As New Button btnSave.BackColor = Drawing.Color.Maroon btnSave.ForeColor = Drawing.Color.White btnSave.Text = "Save" ButtonHolder.Controls.Add(btnSave)I Have also added a code to it as :Public Sub btnhandler_click(ByVal sender As Object, ByVal e As EventArgs) Handles btnhandler.Click Response.Write("clicked") End Subbut this second event code does not execute when i click on the button. Reason???Thanks and Regards,
Apart from what you've already been told, the button needs to be created in the LoadViewState function so that it exists early enough in the page lifecycle for the viewstate to be restored and the event to fire.
Christian Graus - Microsoft MVP - C++ "also I don't think "TranslateOneToTwoBillion OneHundredAndFortySevenMillion FourHundredAndEightyThreeThousand SixHundredAndFortySeven()" is a very good choice for a function name" - SpacixOne ( offering help to someone who really needed it ) ( spaces added for the benefit of people running at < 1280x1024 )
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Dot Net Jantu wrote:
Dim txtname As TextBox txtname = New TextBox txtname.AutoPostBack = False txtname.BackColor = Drawing.Color.AliceBlue txtname.BorderColor = Drawing.Color.Black nameHolder.Controls.Add(txtname)
The description of the
Control.FindControlwhich you said you had read, is as follows: Searches the current naming container for a server control with the specified id parameter. You haven't set theIDproperty for your control. The fact that you have declared a variable calledtxtnameand set it with a reference to your dynamically createdTextBoxobject is not relevent.Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush
hey thanks it worked. I would like to know that do i need to assign a id for the button also? And one more thing will i have to use that find control method in each and every procedure to retrieve the vbalue of the control?
Thanks and Regards,
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hey thanks it worked. I would like to know that do i need to assign a id for the button also? And one more thing will i have to use that find control method in each and every procedure to retrieve the vbalue of the control?
Thanks and Regards,
Dot Net Jantu wrote:
I would like to know that do i need to assign a id for the button also?
You probably should do. You will need to if you want to locate instances of the Button control calling
FindControlon the container object.Dot Net Jantu wrote:
And one more thing will i have to use that find control method in each and every procedure to retrieve the value of the control?
Yes, if you don't already have a reference to one of the controls you will need to call the
FindControlmethod on the container object, passing in its ID to find it.Paul Marfleet "No, his mind is not for rent To any God or government" Tom Sawyer - Rush