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Extract string from CString

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  • CPalliniC CPallini

    That goes against OP title. :-D

    If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
    [my articles]

    modified on Tuesday, February 05, 2008 8:41:55 AM

    R Offline
    R Offline
    Rajkumar R
    wrote on last edited by
    #5

    may be more, but i think it covers what it needed:confused:

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    • CPalliniC CPallini

      That goes against OP title. :-D

      If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
      [my articles]

      modified on Tuesday, February 05, 2008 8:41:55 AM

      M Offline
      M Offline
      Mark Salsbery
      wrote on last edited by
      #6

      What? No solutions that use GetBuffer()?? I am shocked and appalled. :)

      Mark Salsbery Microsoft MVP - Visual C++ :java:

      CPalliniC 1 Reply Last reply
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      • M Mark Salsbery

        What? No solutions that use GetBuffer()?? I am shocked and appalled. :)

        Mark Salsbery Microsoft MVP - Visual C++ :java:

        CPalliniC Offline
        CPalliniC Offline
        CPallini
        wrote on last edited by
        #7

        Only for you, to keep horror alive

        strok(sTemp.GetBuffer(), "Lbl-");

        :-D

        If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
        [my articles]

        In testa che avete, signor di Ceprano?

        M 1 Reply Last reply
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        • CPalliniC CPallini

          Only for you, to keep horror alive

          strok(sTemp.GetBuffer(), "Lbl-");

          :-D

          If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
          [my articles]

          M Offline
          M Offline
          Mark Salsbery
          wrote on last edited by
          #8

          Ahhh yes - the world is balanced again. And bonus points for using the little-known strok() function hehe

          Mark Salsbery Microsoft MVP - Visual C++ :java:

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          • A Anu_Bala

            I have to extract a few character from CString. My CString is like this... Here i have to get the number of Lbl..I mean 10. My code is CString sTemp = {"Tag-10,OnOff-19,Switch-5,Lbl-10,Signal-22,trip-1"}; int pos = sTemp.Find("Lbl-"); Here i get the pos value as 25,then i want to get the character after Lbl- (ie) 10. How can i get ?Pls help me.

            Anu

            R Offline
            R Offline
            Rajesh R Subramanian
            wrote on last edited by
            #9

            Use CString::Mid(), as NishantB++ already said to you.

            CString str = _T("Tag-10,OnOff-19,Switch-5,Lbl-10,Signal-22,trip-1");
            AfxMessageBox(str.Mid(str.Find(_T("Lbl-"))+4,2));//4 and 2 may vary! Depends on your string.

            Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

            R 1 Reply Last reply
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            • R Rajesh R Subramanian

              Use CString::Mid(), as NishantB++ already said to you.

              CString str = _T("Tag-10,OnOff-19,Switch-5,Lbl-10,Signal-22,trip-1");
              AfxMessageBox(str.Mid(str.Find(_T("Lbl-"))+4,2));//4 and 2 may vary! Depends on your string.

              Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

              R Offline
              R Offline
              Rajkumar R
              wrote on last edited by
              #10

              Rajesh R Subramanian wrote:

              4 and 2 may vary!

              I agree with 4 as he knows and is going to search using that string but if he knows 2 that means he already has the string with him and question is to find that string.

              Anu_Bala wrote:

              Here i have to get the number of Lbl..I mean 10.

              R 1 Reply Last reply
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              • R Rajkumar R

                Rajesh R Subramanian wrote:

                4 and 2 may vary!

                I agree with 4 as he knows and is going to search using that string but if he knows 2 that means he already has the string with him and question is to find that string.

                Anu_Bala wrote:

                Here i have to get the number of Lbl..I mean 10.

                R Offline
                R Offline
                Rajesh R Subramanian
                wrote on last edited by
                #11

                Apparently, you did not read the entire comment, did you? It's also mentioned "Depends on your string".

                Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

                R 1 Reply Last reply
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                • R Rajesh R Subramanian

                  Apparently, you did not read the entire comment, did you? It's also mentioned "Depends on your string".

                  Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

                  R Offline
                  R Offline
                  Rajkumar R
                  wrote on last edited by
                  #12

                  then the solution is if he want to find the number of Lbl, when it is 100, he want to build again :omg:

                  Rajesh R Subramanian wrote:

                  "Depends on your string".

                  Depends on the string, lbl10.exe, lbl110.exe ...

                  R 1 Reply Last reply
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                  • R Rajkumar R

                    then the solution is if he want to find the number of Lbl, when it is 100, he want to build again :omg:

                    Rajesh R Subramanian wrote:

                    "Depends on your string".

                    Depends on the string, lbl10.exe, lbl110.exe ...

                    R Offline
                    R Offline
                    Rajesh R Subramanian
                    wrote on last edited by
                    #13

                    My mentioning "Depends on your string" states that he'd have to modify the code accordingly if the parameters change, so that it works always without having to rebuild. I thought it was pretty clear and anyone who fails to understand is just plainly dumb.

                    Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

                    R 1 Reply Last reply
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                    • R Rajesh R Subramanian

                      My mentioning "Depends on your string" states that he'd have to modify the code accordingly if the parameters change, so that it works always without having to rebuild. I thought it was pretty clear and anyone who fails to understand is just plainly dumb.

                      Nobody can give you wiser advice than yourself. - Cicero .·´¯`·->Rajesh<-·´¯`·. Codeproject.com: Visual C++ MVP

                      R Offline
                      R Offline
                      Rajkumar R
                      wrote on last edited by
                      #14

                      Rajesh R Subramanian wrote:

                      to modify the code accordingly if the parameters change

                      that is 2 to 3 when lbl is 100 that means he knows the length of string without the string i got. lbl10.exe no rebuild , lbl-100.exe no rebuild ... thanks :-D recalling ur mentioning of "Depends on your string"

                      Rajesh R Subramanian wrote:

                      //4 and 2 may vary! Depends on your string.

                      Rajesh R Subramanian wrote:

                      plainly dumb.

                      :omg: if he is such a person, i think he never post this, don't u even think, he is in need of this plain dumb solution of counting exercise, as he has NiShantB++ post already.

                      modified on Wednesday, February 06, 2008 11:30:57 PM

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