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lvalue rvalue discussion

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  • M manish patel

    did you read this stetement : "l-values are something that can be at the right side of an '='" It says that if we write x = 10; then x will be l-value(left side value) In c++, we can not give number as variable name, It always be a string only. So in C++, string literals are l-values. Now i think you got it

    Manish Patel. B.E. - Information Technology.

    CPalliniC Online
    CPalliniC Online
    CPallini
    wrote on last edited by
    #10

    manish.patel wrote:

    t says that if we write x = 10; then x will be l-value(left side value) In c++, we can not give number as variable name, It always be a string only. So in C++, string literals are l-values.

    Your argument is wrong. In the expression x = 10; the term x is an identifier, NOT a string literal (a string literal is, for instance, "foo"). See [^]. :)

    If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
    This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

    In testa che avete, signor di Ceprano?

    G 1 Reply Last reply
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    • G George_George

      Thanks NishantB++, Do you agree "in C++, string literals are l-values." in thread http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html[^]? Why? regards, George

      D Offline
      D Offline
      David Crow
      wrote on last edited by
      #11

      George_George wrote:

      Do you agree "in C++, string literals are l-values." in thread http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html\[^\]? Why?

      No, that would mean something like:

      "abc" = "123";

      or

      "myohmy" = 17;

      would be legal.

      "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

      "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

      G 1 Reply Last reply
      0
      • D David Crow

        George_George wrote:

        Do you agree "in C++, string literals are l-values." in thread http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html\[^\]? Why?

        No, that would mean something like:

        "abc" = "123";

        or

        "myohmy" = 17;

        would be legal.

        "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

        "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

        G Offline
        G Offline
        George_George
        wrote on last edited by
        #12

        Hi DavidCrow, Are you sure it can compile?

        #include <string>

        int main()
        {
        "abc" = "123";

        "myohmy" = 17;
        
        return 0;
        

        }

        Compile error,

        1>d:\visual studio 2008\projects\test_string2\test_string2\main.cpp(5) : error C2106: '=' : left operand must be l-value
        1>d:\visual studio 2008\projects\test_string2\test_string2\main.cpp(7) : error C2440: '=' : cannot convert from 'int' to 'const char [7]'

        regards, George

        D 1 Reply Last reply
        0
        • CPalliniC CPallini

          manish.patel wrote:

          t says that if we write x = 10; then x will be l-value(left side value) In c++, we can not give number as variable name, It always be a string only. So in C++, string literals are l-values.

          Your argument is wrong. In the expression x = 10; the term x is an identifier, NOT a string literal (a string literal is, for instance, "foo"). See [^]. :)

          If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
          This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

          G Offline
          G Offline
          George_George
          wrote on last edited by
          #13

          Thanks CPallini, What do you think of whether string literal is lvalue or rvalue? I think it is only rvalue, do you agree? regards, George

          CPalliniC 1 Reply Last reply
          0
          • G George_George

            Thanks CPallini, What do you think of whether string literal is lvalue or rvalue? I think it is only rvalue, do you agree? regards, George

            CPalliniC Online
            CPalliniC Online
            CPallini
            wrote on last edited by
            #14

            George_George wrote:

            What do you think of whether string literal is lvalue or rvalue? I think it is only rvalue, do you agree?

            Yes, of course. Did you ever see a string literal on the left of an assignment expression? :-D

            If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
            This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

            In testa che avete, signor di Ceprano?

            G 1 Reply Last reply
            0
            • G George_George

              Hi DavidCrow, Are you sure it can compile?

              #include <string>

              int main()
              {
              "abc" = "123";

              "myohmy" = 17;
              
              return 0;
              

              }

              Compile error,

              1>d:\visual studio 2008\projects\test_string2\test_string2\main.cpp(5) : error C2106: '=' : left operand must be l-value
              1>d:\visual studio 2008\projects\test_string2\test_string2\main.cpp(7) : error C2440: '=' : cannot convert from 'int' to 'const char [7]'

              regards, George

              D Offline
              D Offline
              David Crow
              wrote on last edited by
              #15

              George_George wrote:

              Are you sure it can compile?

              Of course not. I never said it could. :rolleyes:

              "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

              "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

              G 1 Reply Last reply
              0
              • CPalliniC CPallini

                George_George wrote:

                What do you think of whether string literal is lvalue or rvalue? I think it is only rvalue, do you agree?

                Yes, of course. Did you ever see a string literal on the left of an assignment expression? :-D

                If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke

                G Offline
                G Offline
                George_George
                wrote on last edited by
                #16

                Thanks CPallini, I agree with your reply. I am studying the link as people mention before, http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html[^] in post #2, what do the following statements mean? Especially the additional [2] after "str" and ["str"] after 1? Any ideas?

                * ( ( char * ) & var ) = "str"[2]; // * ((char *)&var) too

                int & varref = var;

                varref = 1["str"]; // varref is also an lvalue

                regards, George

                R 1 Reply Last reply
                0
                • D David Crow

                  George_George wrote:

                  Are you sure it can compile?

                  Of course not. I never said it could. :rolleyes:

                  "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

                  "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

                  G Offline
                  G Offline
                  George_George
                  wrote on last edited by
                  #17

                  Thanks DavidCrow, So, 1. You agree string literal is rvalue? 2. Any comments for, http://www.codeproject.com/script/Forums/View.aspx?fid=1647&msg=2448186[^] regards, George

                  D 1 Reply Last reply
                  0
                  • G George_George

                    Thanks DavidCrow, So, 1. You agree string literal is rvalue? 2. Any comments for, http://www.codeproject.com/script/Forums/View.aspx?fid=1647&msg=2448186[^] regards, George

                    D Offline
                    D Offline
                    David Crow
                    wrote on last edited by
                    #18

                    George_George wrote:

                    1. You agree string literal is rvalue?

                    I already did.

                    "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

                    "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

                    G 1 Reply Last reply
                    0
                    • D David Crow

                      George_George wrote:

                      1. You agree string literal is rvalue?

                      I already did.

                      "Normal is getting dressed in clothes that you buy for work and driving through traffic in a car that you are still paying for, in order to get to the job you need to pay for the clothes and the car and the house you leave vacant all day so you can afford to live in it." - Ellen Goodman

                      "To have a respect for ourselves guides our morals; to have deference for others governs our manners." - Laurence Sterne

                      G Offline
                      G Offline
                      George_George
                      wrote on last edited by
                      #19

                      Thanks DavidCrow, Any comments to? http://www.codeproject.com/script/Forums/View.aspx?fid=1647&msg=2448186[^] regards, George

                      1 Reply Last reply
                      0
                      • G George_George

                        Thanks CPallini, I agree with your reply. I am studying the link as people mention before, http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html[^] in post #2, what do the following statements mean? Especially the additional [2] after "str" and ["str"] after 1? Any ideas?

                        * ( ( char * ) & var ) = "str"[2]; // * ((char *)&var) too

                        int & varref = var;

                        varref = 1["str"]; // varref is also an lvalue

                        regards, George

                        R Offline
                        R Offline
                        Rajkumar R
                        wrote on last edited by
                        #20

                        George_George wrote:

                        in post #2, what do the following statements mean? Especially the additional [2] after "str" and ["str"] after 1? Any ideas?

                        George_George wrote:

                        * ( ( char * ) & var ) = "str"[2]; // * ((char *)&var) too

                        it is nothing but subscripting an array, here "str" is an constant array of string. it is same as

                        const char * const szText = "str"; or const char szText[] = {"str"};
                        * ( ( char * ) & var ) = szText[2];

                        George_George wrote:

                        varref = 1["str"]; // varref is also an lvalue

                        "the subscript operator [] is interpreted in such a way that E1[E2] is identical to *((E1)+(E2))" from C++ std. I think 1["str"] is tricking the above expression to *((1) + (pointer to "str")) that is same as "str"[1] which evaluates to *((pointer to "str") + (1)). because adding pointer to index and index to pointer is same.

                        G 1 Reply Last reply
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                        • R Rajkumar R

                          George_George wrote:

                          in post #2, what do the following statements mean? Especially the additional [2] after "str" and ["str"] after 1? Any ideas?

                          George_George wrote:

                          * ( ( char * ) & var ) = "str"[2]; // * ((char *)&var) too

                          it is nothing but subscripting an array, here "str" is an constant array of string. it is same as

                          const char * const szText = "str"; or const char szText[] = {"str"};
                          * ( ( char * ) & var ) = szText[2];

                          George_George wrote:

                          varref = 1["str"]; // varref is also an lvalue

                          "the subscript operator [] is interpreted in such a way that E1[E2] is identical to *((E1)+(E2))" from C++ std. I think 1["str"] is tricking the above expression to *((1) + (pointer to "str")) that is same as "str"[1] which evaluates to *((pointer to "str") + (1)). because adding pointer to index and index to pointer is same.

                          G Offline
                          G Offline
                          George_George
                          wrote on last edited by
                          #21

                          Great Rajkumar!! Cool reply. For this discussion, http://www.velocityreviews.com/forums/t279868-what-is-lvalue.html[^] It is mentioned,

                          struct C
                          {
                          C& operator=(int);
                          };

                          C() = 5; // OK to assign to r-value C();

                          Here is the related description, -------------------- True. But there are compilers (eg VC++) that do allow to bind non-const references to temporary as an extension of the standard. IMO, a conforming compiler should reject the code. -------------------- I can not see in above code there occurs "bind non-const references to temporary". Do you see it occurs? regards, George

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