Passing value to base class

[humayunlalzad]

class MyClass
{

    public MyClass(int b)
    {
        Console.WriteLine(b);
    }

    public MyClass()
        : this(43)
    {
        Console.WriteLine("Default Const");
    }
}
class MyClass2 : myClass 
{
 
    public MyClass2(int b) : base(b) 
    {
        Console.WriteLine(b);
    }

    public MyClass2()
        
    {
        Console.WriteLine("Default Const");
    }
}

In the above code in my MyClass2 non- default constructor. It is giving a value back to the base class. I want to know if at the same time can I make the default constructor run. I mean something like this

public MyClass2(int b) : base(b),this()

or this

public MyClass2(int b) : base(b) : this()

How do I do it

[led mike]

humayunlalzad wrote:

How do I do it

Best practice would be to refactor the code out into a member function so that it can be called.

led mike

[leppie]

humayunlalzad wrote:

public MyClass2(int b) : base(b),this() or this public MyClass2(int b) : base(b) : this()

Does not compute! :) Why not just set the values in the constructor and make life easier for yourself? :)

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[Richard Blythe]

The best approach would be something like this:

;
class MyClass2 : myClass
{
public MyClass2(int b) : base(b)
{
Console.WriteLine(b);
}

public MyClass2() : base(THE CONST VALUE) //<------------------     
{         
    Console.WriteLine("Default Const");     
} 


private void 

}

"Make it as simple as possible, but no simpler" Issac Newton