What is wrong in this strcpy()?
-
What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }
-
Even when i change s1 to char *s1="TEMP"; strcpy(s1,p); // resulting in error.
-
One suggestion
Member 5502879 wrote:
char * p=(char*) malloc(strlen(s)); p=s;
you allocating buffer and assigning some other pointer to p again. this will cause memory leak.
Regards, Sandip.
Even if do not create 'p' and directly copy s to s1, strcpy(s1,s); im still getting the same error.
-
Even if do not create 'p' and directly copy s to s1, strcpy(s1,s); im still getting the same error.
Try allocating memory to s1 before you copy stuff into it and then tell if it crashes. If it doesn't, well, guess why. :)
Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche .·´¯`·->Rajesh<-·´¯`·. [Microsoft MVP - Visual C++]
-
Even if do not create 'p' and directly copy s to s1, strcpy(s1,s); im still getting the same error.
-
What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }
try allocate memory like this: char * s_cpy(char * s,char * s1) { char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; } don forget to free them up later or you will encounter memory leak...
-
try allocate memory like this: char * s_cpy(char * s,char * s1) { char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; } don forget to free them up later or you will encounter memory leak...
auralius wrote:
char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s;
And what's the point of doing the above? :)
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles] -
What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }
I see two issues.
Member 5502879 wrote:
char * p=(char*) malloc(strlen(s)); p=s;
You've reassigned
pto some other address. This will cause problems if you go to free the address returned bymalloc().Member 5502879 wrote:
strcpy(s1,p); //error, test.exe has encountered a problem
Because
s1has not been allocated any memory.strcpy()is therefore dereferencing a null pointer."Love people and use things, not love things and use people." - Unknown
"The brick walls are there for a reason...to stop the people who don't want it badly enough." - Randy Pausch
-
What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }
Several things are wrong. As pointed out, s1 is allocated as just a pointer to a string so you cannot copy data to it. In addition, you allocated only strlen bytes for the p copy, you need to allocate strlen+1 to allow the terminating null for string s. You may get away with this if a paragraph (16 bytes) is probably allocated for the malloc, but it is still bad code.
-
auralius wrote:
char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s;
And what's the point of doing the above? :)
If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles] -
What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }
I observed following issues 1) Issue of Memory allocation 2) this is the case where we can understand the Global an Local variable concept. Try to name ur sencond argument in list with different name. May be it will work.
The secret of life is not enjoyment but education through experience. - Swami Vivekananda.
-
allocating memory so i won't be a NULL pointer anymore... :)
char * p =(char*) malloc(strlen(s)+1);
s1 = (char*) malloc(10); //use this!!!!
p=s;allocating memory for
pand then settingp=s;make no sense to me. :)If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles] -
char * p =(char*) malloc(strlen(s)+1);
s1 = (char*) malloc(10); //use this!!!!
p=s;allocating memory for
pand then settingp=s;make no sense to me. :)If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]yup, i know...i meant allocating memory for s1.. my concern wasn't on part where p=s. i thought application crashed due to NULL pointer on s1...that's why we must allocate memory for s1... :-D
