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  4. What is wrong in this strcpy()?

What is wrong in this strcpy()?

Scheduled Pinned Locked Moved C / C++ / MFC
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  • U User 5495012

    Even if do not create 'p' and directly copy s to s1, strcpy(s1,s); im still getting the same error.

    R Offline
    R Offline
    Rajesh R Subramanian
    wrote on last edited by
    #10

    Try allocating memory to s1 before you copy stuff into it and then tell if it crashes. If it doesn't, well, guess why. :)

    Many are stubborn in pursuit of the path they have chosen, few in pursuit of the goal - Friedrich Nietzsche .·´¯`·->Rajesh<-·´¯`·. [Microsoft MVP - Visual C++]

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    • U User 5495012

      Even if do not create 'p' and directly copy s to s1, strcpy(s1,s); im still getting the same error.

      S Offline
      S Offline
      SandipG
      wrote on last edited by
      #11

      I did not answer you why it crashes.. others have already told you the reason. I just pointed the mistake.

      Regards, Sandip.

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      • U User 5495012

        What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }

        A Offline
        A Offline
        auralius manurung
        wrote on last edited by
        #12

        try allocate memory like this: char * s_cpy(char * s,char * s1) { char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; } don forget to free them up later or you will encounter memory leak...

        CPalliniC 1 Reply Last reply
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        • A auralius manurung

          try allocate memory like this: char * s_cpy(char * s,char * s1) { char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; } don forget to free them up later or you will encounter memory leak...

          CPalliniC Offline
          CPalliniC Offline
          CPallini
          wrote on last edited by
          #13

          auralius wrote:

          char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s;

          And what's the point of doing the above? :)

          If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
          This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
          [My articles]

          In testa che avete, signor di Ceprano?

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          • U User 5495012

            What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }

            D Offline
            D Offline
            David Crow
            wrote on last edited by
            #14

            I see two issues.

            Member 5502879 wrote:

            char * p=(char*) malloc(strlen(s)); p=s;

            You've reassigned p to some other address. This will cause problems if you go to free the address returned by malloc().

            Member 5502879 wrote:

            strcpy(s1,p); //error, test.exe has encountered a problem

            Because s1 has not been allocated any memory. strcpy() is therefore dereferencing a null pointer.

            "Love people and use things, not love things and use people." - Unknown

            "The brick walls are there for a reason...to stop the people who don't want it badly enough." - Randy Pausch

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            • U User 5495012

              What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }

              M Offline
              M Offline
              Member 4194593
              wrote on last edited by
              #15

              Several things are wrong. As pointed out, s1 is allocated as just a pointer to a string so you cannot copy data to it. In addition, you allocated only strlen bytes for the p copy, you need to allocate strlen+1 to allow the terminating null for string s. You may get away with this if a paragraph (16 bytes) is probably allocated for the malloc, but it is still bad code.

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              • CPalliniC CPallini

                auralius wrote:

                char * p =(char*) malloc(strlen(s)+1); s1 = (char*) malloc(10); //use this!!!! p=s;

                And what's the point of doing the above? :)

                If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                [My articles]

                A Offline
                A Offline
                auralius manurung
                wrote on last edited by
                #16

                allocating memory so i won't be a NULL pointer anymore... :)

                CPalliniC 1 Reply Last reply
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                • U User 5495012

                  What is wrong in this strcpy()? I tried this function call, no compile time errors, but results in error during runtime. What could be the problem in that function call? char *s= "TEST"; char *s1= NULL; char * s_cpy(char * s,char * s1) { char * p=(char*) malloc(strlen(s)); p=s; printf("%s\n",p); // prints TEST printf("%s\n",s1); // prints printf("%s\n",s); // prints TEST strcpy(s1,p); //error, test.exe has encountered a problem return s1; }

                  M Offline
                  M Offline
                  Mahesh Kulkarni
                  wrote on last edited by
                  #17

                  I observed following issues 1) Issue of Memory allocation 2) this is the case where we can understand the Global an Local variable concept. Try to name ur sencond argument in list with different name. May be it will work.

                  The secret of life is not enjoyment but education through experience. - Swami Vivekananda.

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                  • A auralius manurung

                    allocating memory so i won't be a NULL pointer anymore... :)

                    CPalliniC Offline
                    CPalliniC Offline
                    CPallini
                    wrote on last edited by
                    #18

                    char * p =(char*) malloc(strlen(s)+1);
                    s1 = (char*) malloc(10); //use this!!!!
                    p=s;

                    allocating memory for p and then setting p=s; make no sense to me. :)

                    If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                    This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                    [My articles]

                    In testa che avete, signor di Ceprano?

                    A 1 Reply Last reply
                    0
                    • CPalliniC CPallini

                      char * p =(char*) malloc(strlen(s)+1);
                      s1 = (char*) malloc(10); //use this!!!!
                      p=s;

                      allocating memory for p and then setting p=s; make no sense to me. :)

                      If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
                      This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
                      [My articles]

                      A Offline
                      A Offline
                      auralius manurung
                      wrote on last edited by
                      #19

                      yup, i know...i meant allocating memory for s1.. my concern wasn't on part where p=s. i thought application crashed due to NULL pointer on s1...that's why we must allocate memory for s1... :-D

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