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  4. BinaryFormatter: Serializing an object's base class

BinaryFormatter: Serializing an object's base class

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  • M Mark Salsbery

    Ennis Ray Lynch, Jr. wrote:

    For standard XML serializaiton the default constructor needs to be public

    What if there's no default constructor?

    Ennis Ray Lynch, Jr. wrote:

    For binary serializaiton you need to have the serialization constructor defined.

    Not true. That's only for ISerializable-derived classes. ISerializable isn't required for binary serialization.

    Mark Salsbery Microsoft MVP - Visual C++ :java:

    E Offline
    E Offline
    Ennis Ray Lynch Jr
    wrote on last edited by
    #17

    I will believe you on the second one, however, a default constructor is defined by default unless you create either a non-default constructor or a default constructor with visibility other than public. See: http://support.microsoft.com/kb/330592[^]

    public class Foo{

    }

    and

    public class Foo{
    public Foo(){}
    }

    Both contain default constructors whereas

    public class Foo{
    public Foo(int a){}
    }

    and

    public class Foo{
    private Foo(){}
    }

    Do not.

    Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
    Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
    Most of this sig is for Google, not ego.

    M 2 Replies Last reply
    0
    • E Ennis Ray Lynch Jr

      I will believe you on the second one, however, a default constructor is defined by default unless you create either a non-default constructor or a default constructor with visibility other than public. See: http://support.microsoft.com/kb/330592[^]

      public class Foo{

      }

      and

      public class Foo{
      public Foo(){}
      }

      Both contain default constructors whereas

      public class Foo{
      public Foo(int a){}
      }

      and

      public class Foo{
      private Foo(){}
      }

      Do not.

      Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
      Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
      Most of this sig is for Google, not ego.

      M Offline
      M Offline
      Mark Salsbery
      wrote on last edited by
      #18

      Ennis Ray Lynch, Jr. wrote:

      a default constructor is defined by default unless you create either a non-default constructor or a default constructor with visibility other than public.

      Got it, thanks :) Mark

      Mark Salsbery Microsoft MVP - Visual C++ :java:

      1 Reply Last reply
      0
      • E Ennis Ray Lynch Jr

        I will believe you on the second one, however, a default constructor is defined by default unless you create either a non-default constructor or a default constructor with visibility other than public. See: http://support.microsoft.com/kb/330592[^]

        public class Foo{

        }

        and

        public class Foo{
        public Foo(){}
        }

        Both contain default constructors whereas

        public class Foo{
        public Foo(int a){}
        }

        and

        public class Foo{
        private Foo(){}
        }

        Do not.

        Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
        Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
        Most of this sig is for Google, not ego.

        M Offline
        M Offline
        Mark Salsbery
        wrote on last edited by
        #19

        Also, the constructor is only called when using XmlSerializer. No constructor is called with binary/SOAP deserialization. Cheers, Mark

        Mark Salsbery Microsoft MVP - Visual C++ :java:

        E 1 Reply Last reply
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        • M Mark Salsbery

          Also, the constructor is only called when using XmlSerializer. No constructor is called with binary/SOAP deserialization. Cheers, Mark

          Mark Salsbery Microsoft MVP - Visual C++ :java:

          E Offline
          E Offline
          Ennis Ray Lynch Jr
          wrote on last edited by
          #20

          I didn't know that, I just assumed a constructor would be called.

          Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
          Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
          Most of this sig is for Google, not ego.

          M 1 Reply Last reply
          0
          • M Mark Salsbery

            What if you make the Dog class [Serializable], mark all its members [NonSerialized], and use a SerializationBinder[^] for deserialization? I'm not sure if it will work or not :)

            Mark Salsbery Microsoft MVP - Visual C++ :java:

            M Offline
            M Offline
            mav northwind
            wrote on last edited by
            #21

            Thanks for the suggestion, I'll take a look. Jeez, I didn't expect it to get so complicated... ;P

            Regards, mav -- Black holes are the places where God divided by 0...

            M 2 Replies Last reply
            0
            • E Ennis Ray Lynch Jr

              I didn't know that, I just assumed a constructor would be called.

              Need software developed? Offering C# development all over the United States, ERL GLOBAL, Inc is the only call you will have to make.
              Happiness in intelligent people is the rarest thing I know. -- Ernest Hemingway
              Most of this sig is for Google, not ego.

              M Offline
              M Offline
              Mark Salsbery
              wrote on last edited by
              #22

              I was trying to convince myself more than you I think :) I knew I read it somewhere once, and testing confirmed it. Its obscurely "documented" here[^]. I appreciate the discussion, thanks! Mark

              Mark Salsbery Microsoft MVP - Visual C++ :java:

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              • M mav northwind

                Thanks for the suggestion, I'll take a look. Jeez, I didn't expect it to get so complicated... ;P

                Regards, mav -- Black holes are the places where God divided by 0...

                M Offline
                M Offline
                Mark Salsbery
                wrote on last edited by
                #23

                I was bored, so I tried it. Works great :)

                \[Serializable\]
                public class Animal
                {
                	public string str
                	{
                		get;
                		set;
                	}
                }
                
                \[Serializable\]
                public class Dog : Animal
                {
                	\[NonSerialized\]  `//<-- Optional!`
                	public Int32 A;
                
                	\[NonSerialized\]  `//<-- Optional!`
                	public Int32 B;
                
                	public Dog()
                	{
                		A = 5;
                		B = 10;
                	}
                }
                
                sealed class DogToAnimalDeserializationBinder : SerializationBinder
                {
                	public override Type BindToType(string assemblyName, string typeName)
                	{
                		Type typeToDeserialize = null;
                
                		String assemVer1 = Assembly.GetExecutingAssembly().FullName;
                		String typeVer1 = "Dog";
                
                		if (assemblyName == assemVer1 && typeName == typeVer1)
                		{
                			typeName = "Animal";
                		}
                
                		// The following line of code returns the type.
                		typeToDeserialize = Type.GetType(String.Format("{0}, {1}",
                			typeName, assemblyName));
                
                		return typeToDeserialize;
                	}
                }
                

                ...

                Dog dog = new Dog();
                dog.A = 3;
                dog.B = 5;
                dog.str = "Animal String";

                MemoryStream MemStream = new MemoryStream();

                // Serialize a Dog object
                BinaryFormatter Serializer = new BinaryFormatter();
                Serializer.Serialize(MemStream, dog);

                MemStream.Seek(0, SeekOrigin.Begin);

                // Deserialize as an Animal object
                Serializer.Binder = new DogToAnimalDeserializationBinder();
                Animal animal = (Animal)Serializer.Deserialize(MemStream);

                Mark Salsbery Microsoft MVP - Visual C++ :java:

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                • M mav northwind

                  Thanks for the suggestion, I'll take a look. Jeez, I didn't expect it to get so complicated... ;P

                  Regards, mav -- Black holes are the places where God divided by 0...

                  M Offline
                  M Offline
                  Mark Salsbery
                  wrote on last edited by
                  #24

                  Wow - my code was overcomplicated. The Binder there is completely unnecessary :rolleyes:

                  mav.northwind wrote:

                  The other side of the line (where the object is supposed to be deserialized) doesn't know about Dogs, it only knows about Animals (i.e. there's only the assembly defining Animal available, not the one defining Dog, so trying to deserialize this object will throw a TypeLoadException).

                  I just noticed that post. The only way that's going to work is to serialize an Animal object in the first place, as you already know. The deserializing end could use a custom binder to deserialize a Dog, but that would still require that end to have the assembly implementing the Dog class. Basically I helped get you back where you started, sorry! :)

                  Mark Salsbery Microsoft MVP - Visual C++ :java:

                  M 1 Reply Last reply
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                  • M Mark Salsbery

                    Wow - my code was overcomplicated. The Binder there is completely unnecessary :rolleyes:

                    mav.northwind wrote:

                    The other side of the line (where the object is supposed to be deserialized) doesn't know about Dogs, it only knows about Animals (i.e. there's only the assembly defining Animal available, not the one defining Dog, so trying to deserialize this object will throw a TypeLoadException).

                    I just noticed that post. The only way that's going to work is to serialize an Animal object in the first place, as you already know. The deserializing end could use a custom binder to deserialize a Dog, but that would still require that end to have the assembly implementing the Dog class. Basically I helped get you back where you started, sorry! :)

                    Mark Salsbery Microsoft MVP - Visual C++ :java:

                    M Offline
                    M Offline
                    mav northwind
                    wrote on last edited by
                    #25

                    Hmmm, I've played around with the SerializationBinder a bit, but didn't get a useable result either. If I always return typeof(Animal) as target type in BindToType, then the deserializing end doesn't require knowledge about Dog, but unfortunately it doesn't work because then even Animal's properties aren't deserialized if I have a Dog object in my serialization stream. :(

                    Regards, mav -- Black holes are the places where God divided by 0...

                    M 1 Reply Last reply
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                    • G Giorgi Dalakishvili

                      See if this helps: Advanced Binary Serialization: Deserializing an Object Into a Different Type Than the One It was Serialized Into[^]

                      Giorgi Dalakishvili #region signature My Articles / My Latest Article[^] / My blog[^] #endregion

                      M Offline
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                      mav northwind
                      wrote on last edited by
                      #26

                      Thanks for the link, it was quite instructive, although I couldn't achieve useable results so far with a SerializationBinder... Nevertheless: thanks for taking your time.

                      Regards, mav -- Black holes are the places where God divided by 0...

                      1 Reply Last reply
                      0
                      • M mav northwind

                        Hmmm, I've played around with the SerializationBinder a bit, but didn't get a useable result either. If I always return typeof(Animal) as target type in BindToType, then the deserializing end doesn't require knowledge about Dog, but unfortunately it doesn't work because then even Animal's properties aren't deserialized if I have a Dog object in my serialization stream. :(

                        Regards, mav -- Black holes are the places where God divided by 0...

                        M Offline
                        M Offline
                        Mark Salsbery
                        wrote on last edited by
                        #27

                        Right. The only way I can see to do it, if the deserialization end has no access to the Dog class (or an equivalent class), is to add a method to Dog that returns an Animal object and serialize that object. It's really unconventional anyway....it generally doesn't make sense to only serialize the base class portion of an object. But if you have a special need I suppose you need a special solution. :) Mark

                        Mark Salsbery Microsoft MVP - Visual C++ :java:

                        M 1 Reply Last reply
                        0
                        • M Mark Salsbery

                          Right. The only way I can see to do it, if the deserialization end has no access to the Dog class (or an equivalent class), is to add a method to Dog that returns an Animal object and serialize that object. It's really unconventional anyway....it generally doesn't make sense to only serialize the base class portion of an object. But if you have a special need I suppose you need a special solution. :) Mark

                          Mark Salsbery Microsoft MVP - Visual C++ :java:

                          M Offline
                          M Offline
                          mav northwind
                          wrote on last edited by
                          #28

                          I think I got it! After your and Giorgi's hints concerning the SerializationBinder, I looked at BinaryFormatter's other properties and found SurrogateSelector and subsequently ISerializationSurrogate. Using these two interfaces I was able to control the serialization process in a way that only Animal's properties are being serialized and during deserialization a real Animal object is being created. This should do the trick... Thanks for taking your time!

                          Regards, mav -- Black holes are the places where God divided by 0...

                          M 1 Reply Last reply
                          0
                          • M mav northwind

                            I think I got it! After your and Giorgi's hints concerning the SerializationBinder, I looked at BinaryFormatter's other properties and found SurrogateSelector and subsequently ISerializationSurrogate. Using these two interfaces I was able to control the serialization process in a way that only Animal's properties are being serialized and during deserialization a real Animal object is being created. This should do the trick... Thanks for taking your time!

                            Regards, mav -- Black holes are the places where God divided by 0...

                            M Offline
                            M Offline
                            Mark Salsbery
                            wrote on last edited by
                            #29

                            Very cool! Thanks for the update! Cheers, Mark

                            Mark Salsbery Microsoft MVP - Visual C++ :java:

                            1 Reply Last reply
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