Changing the Length of String from 8-Bits to 16-Bits Number

[Neelesh K J Jain]

Hello All, I am want to convert the length of a string to a Hexa-Decimal number as a 16 Bits. So Using the _itoa(cLengthOfString,strlen(strSource),16) where cLengthOfString is char [5] and strSource is a char * but when i observe the destination string is having length represented in 8-bits character, I want it in 16 bits character, for e.g., xFFFF should utilize only 2 bytes, instead of 4 bytes. Thanks, Neelesh K J Jain.

[CPallini]

To represent a integer in the range {0,65535} as hexadecimal (ANSI) string you need 4 characters. The binary encoding of such a number is (of course) 16 bits (i.e. 2 bytes) wide.

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[led mike]

Neelesh K J Jain wrote:

for e.g., xFFFF should utilize only 2 bytes, instead of 4 bytes.

What? How the hell is that going to happen? Run the following code and see if you get a clue.

char buf[5];
itoa( 0xf, buf, 16);
cout << buf << endl;
itoa( 0xff, buf, 16);
cout << buf << endl;
itoa( 0xfff, buf, 16);
cout << buf << endl;
itoa( 0xffff, buf, 16);
cout << buf << endl;