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Working with multiple forms

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  • D DaveyM69

    If I understand you correctly, you want to get a value from the second Form in the first? If so, create a public property or method in the second Form, and call that from the first using the instance of the second Form.

    // form2 is the Form2 instance and TextIWant is a string property getter in Form2
    string specialText = form2.TextIWant

    Dave
    BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)
    Visual Basic is not used by normal people so we're not covering it here. (Uncyclopedia)
    Why are you using VB6? Do you hate yourself? (Christian Graus)

    B Offline
    B Offline
    bwood2020
    wrote on last edited by
    #5

    Yes, that is correct. I want to capture the value from the second form and use it in the first. in the second form I have this: public void textBox1_TextChanged(object sender, EventArgs e) { string GD; GD = textBox1.Text; } then I am calling it in the first form with this: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=""text;HDR=YES;FMT=Delimited("+ GD +")"; Both methods were made public before posting. Should have mentioned that. When I declare another string in the first it only allows me to write: string GDS = GetDelimiter.GD This throws an error: Doesn't contain a definition for GD.

    D 1 Reply Last reply
    0
    • B bwood2020

      Yes, that is correct. I want to capture the value from the second form and use it in the first. in the second form I have this: public void textBox1_TextChanged(object sender, EventArgs e) { string GD; GD = textBox1.Text; } then I am calling it in the first form with this: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=""text;HDR=YES;FMT=Delimited("+ GD +")"; Both methods were made public before posting. Should have mentioned that. When I declare another string in the first it only allows me to write: string GDS = GetDelimiter.GD This throws an error: Doesn't contain a definition for GD.

      D Offline
      D Offline
      DaveyM69
      wrote on last edited by
      #6

      Keep a reference to the second form when you instanciate it and use that reference. A simple example. Button on Form1, TextBox on Form2:

      // Form1
      using System;
      using System.Windows.Forms;

      namespace WindowsFormsApplication1
      {
      public partial class Form1 : Form
      {
      private Form2 form2;
      public Form1()
      {
      InitializeComponent();
      form2 = new Form2();
      form2.Show();
      }

          private void button1\_Click(object sender, EventArgs e)
          {
              if (form2 != null)
                  MessageBox.Show(form2.GD);
          }
      }
      

      }

      // Form2
      using System;
      using System.Windows.Forms;

      namespace WindowsFormsApplication1
      {
      public partial class Form2 : Form
      {
      public Form2()
      {
      InitializeComponent();
      }

          private void textBox1\_TextChanged(object sender, EventArgs e)
          {
              GD = textBox1.Text;
          }
      
          public string GD
          {
              get;
              set;
          }
      }
      

      }

      Dave
      BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)
      Visual Basic is not used by normal people so we're not covering it here. (Uncyclopedia)
      Why are you using VB6? Do you hate yourself? (Christian Graus)

      B 1 Reply Last reply
      0
      • D DaveyM69

        Keep a reference to the second form when you instanciate it and use that reference. A simple example. Button on Form1, TextBox on Form2:

        // Form1
        using System;
        using System.Windows.Forms;

        namespace WindowsFormsApplication1
        {
        public partial class Form1 : Form
        {
        private Form2 form2;
        public Form1()
        {
        InitializeComponent();
        form2 = new Form2();
        form2.Show();
        }

            private void button1\_Click(object sender, EventArgs e)
            {
                if (form2 != null)
                    MessageBox.Show(form2.GD);
            }
        }
        

        }

        // Form2
        using System;
        using System.Windows.Forms;

        namespace WindowsFormsApplication1
        {
        public partial class Form2 : Form
        {
        public Form2()
        {
        InitializeComponent();
        }

            private void textBox1\_TextChanged(object sender, EventArgs e)
            {
                GD = textBox1.Text;
            }
        
            public string GD
            {
                get;
                set;
            }
        }
        

        }

        Dave
        BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)
        Visual Basic is not used by normal people so we're not covering it here. (Uncyclopedia)
        Why are you using VB6? Do you hate yourself? (Christian Graus)

        B Offline
        B Offline
        bwood2020
        wrote on last edited by
        #7

        Having a problem with get and set. The error I receive for: public void textBox1_TextChanged(object sender, EventArgs e) { GD = textBox1.Text; } public string GD { get; set; } Error: get and set must declare a body because it is not marked abstract or extern. I tried adding some code to get and set and I received this error: public void textBox1_TextChanged(object sender, EventArgs e) { //GD = textBox1.Text; } public string GD { get { return GD; } set { GD = value; } } Error:Make sure you do not have an infinite loop or infinite recursion. Any ideas?

        H D 2 Replies Last reply
        0
        • B bwood2020

          Having a problem with get and set. The error I receive for: public void textBox1_TextChanged(object sender, EventArgs e) { GD = textBox1.Text; } public string GD { get; set; } Error: get and set must declare a body because it is not marked abstract or extern. I tried adding some code to get and set and I received this error: public void textBox1_TextChanged(object sender, EventArgs e) { //GD = textBox1.Text; } public string GD { get { return GD; } set { GD = value; } } Error:Make sure you do not have an infinite loop or infinite recursion. Any ideas?

          H Offline
          H Offline
          Henry Minute
          wrote on last edited by
          #8

          The problem is caused by your new public property. Change the case of the field references. Change:

          public string GD
          {
          get { return GD; } // this is calling this property and so goes round in circles
          set { GD = value; } // same here
          }

          to:

          public string GD
          {
          get { return gd; } // now referencing your private field, assuming that you called it 'gd'
          set { gd = value; } // same here
          }

          Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

          B 1 Reply Last reply
          0
          • B bwood2020

            Having a problem with get and set. The error I receive for: public void textBox1_TextChanged(object sender, EventArgs e) { GD = textBox1.Text; } public string GD { get; set; } Error: get and set must declare a body because it is not marked abstract or extern. I tried adding some code to get and set and I received this error: public void textBox1_TextChanged(object sender, EventArgs e) { //GD = textBox1.Text; } public string GD { get { return GD; } set { GD = value; } } Error:Make sure you do not have an infinite loop or infinite recursion. Any ideas?

            D Offline
            D Offline
            DaveyM69
            wrote on last edited by
            #9

            Sorry, I was using automatic properties which may not be available in the version that you're working with. Follow Henry's advice and use a private member variable that the property getter and setter accesses.

            Dave
            BTW, in software, hope and pray is not a viable strategy. (Luc Pattyn)
            Visual Basic is not used by normal people so we're not covering it here. (Uncyclopedia)
            Why are you using VB6? Do you hate yourself? (Christian Graus)

            1 Reply Last reply
            0
            • H Henry Minute

              The problem is caused by your new public property. Change the case of the field references. Change:

              public string GD
              {
              get { return GD; } // this is calling this property and so goes round in circles
              set { GD = value; } // same here
              }

              to:

              public string GD
              {
              get { return gd; } // now referencing your private field, assuming that you called it 'gd'
              set { gd = value; } // same here
              }

              Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

              B Offline
              B Offline
              bwood2020
              wrote on last edited by
              #10

              Sorry, I'm not following. As you can guess I am not a very good programmer. Just starting out and I thank you for your patience. I do not have any private fields in the second form. Do I need to declare gd as private? Something like: public void textBox1_TextChanged(object sender, EventArgs e) { GD = textBox1.Text; gd = GD; } private string gd; public string GD { get { return gd; } set { gd = value; } }

              H 1 Reply Last reply
              0
              • B bwood2020

                Sorry, I'm not following. As you can guess I am not a very good programmer. Just starting out and I thank you for your patience. I do not have any private fields in the second form. Do I need to declare gd as private? Something like: public void textBox1_TextChanged(object sender, EventArgs e) { GD = textBox1.Text; gd = GD; } private string gd; public string GD { get { return gd; } set { gd = value; } }

                H Offline
                H Offline
                Henry Minute
                wrote on last edited by
                #11

                Almost right. Well worked out! just a small change

                public void textBox1_TextChanged(object sender, EventArgs e)
                {

                GD = textBox1.Text;
                gd = GD; // this line is not needed. When you say GD = textBox1.Text, the lines in the set part of GD
                // (called the setter, guess what the get part is called) get executed; gd = value.
                // The value is whatever is on the right of the = in GD = textBox1.Text

                }
                private string gd;
                public string GD
                {
                get { return gd; }
                set { gd = value; }
                }

                Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                B 1 Reply Last reply
                0
                • H Henry Minute

                  Almost right. Well worked out! just a small change

                  public void textBox1_TextChanged(object sender, EventArgs e)
                  {

                  GD = textBox1.Text;
                  gd = GD; // this line is not needed. When you say GD = textBox1.Text, the lines in the set part of GD
                  // (called the setter, guess what the get part is called) get executed; gd = value.
                  // The value is whatever is on the right of the = in GD = textBox1.Text

                  }
                  private string gd;
                  public string GD
                  {
                  get { return gd; }
                  set { gd = value; }
                  }

                  Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                  B Offline
                  B Offline
                  bwood2020
                  wrote on last edited by
                  #12

                  All right, it works!!! One more issue though. I placed a messageBox in the code on the first form and I am getting the correct string delimiter. So I know GD is storing this, however, when I go to call GetDelimiter.GD for the in the connection I get an ArgumentException was unhandled error: Format of the initialization string does not conform to specification starting at index 85. Here is the connection string: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=""text;HDR=YES;FMT=Delimited["+ GetDelimiterForm.GD +"]"; The error occures at: OleDbConnection conTXT = new OleDbConnection(comString); I know it has something to do with FMT=Delimited["+ GetDelimiterForm.GD +"]"; because if I hard code it it has no problems (FMT=Delimiter(TAB)""";). I have tried replacing "[" with "(" and that doesn't work. Any ideas on this one?

                  H 1 Reply Last reply
                  0
                  • B bwood2020

                    All right, it works!!! One more issue though. I placed a messageBox in the code on the first form and I am getting the correct string delimiter. So I know GD is storing this, however, when I go to call GetDelimiter.GD for the in the connection I get an ArgumentException was unhandled error: Format of the initialization string does not conform to specification starting at index 85. Here is the connection string: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=""text;HDR=YES;FMT=Delimited["+ GetDelimiterForm.GD +"]"; The error occures at: OleDbConnection conTXT = new OleDbConnection(comString); I know it has something to do with FMT=Delimited["+ GetDelimiterForm.GD +"]"; because if I hard code it it has no problems (FMT=Delimiter(TAB)""";). I have tried replacing "[" with "(" and that doesn't work. Any ideas on this one?

                    H Offline
                    H Offline
                    Henry Minute
                    wrote on last edited by
                    #13

                    When you hard code it you are using slightly different syntax Hard coded: FMT=Delimiter(TAB) Using GetDelimiterForm: FMT=Delimited[...... Delimiter and Delimited, or is that just a typo?

                    Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                    B 1 Reply Last reply
                    0
                    • H Henry Minute

                      When you hard code it you are using slightly different syntax Hard coded: FMT=Delimiter(TAB) Using GetDelimiterForm: FMT=Delimited[...... Delimiter and Delimited, or is that just a typo?

                      Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                      B Offline
                      B Offline
                      bwood2020
                      wrote on last edited by
                      #14

                      I apologize, it was a typo. What I meant was Hard Coded: FMT=Delimited(TAB) \\This works Using GetDelimiterForm: FMT=Delimited["+ GetDelimiterForm.GD +"]\\This throws the error

                      H 1 Reply Last reply
                      0
                      • B bwood2020

                        I apologize, it was a typo. What I meant was Hard Coded: FMT=Delimited(TAB) \\This works Using GetDelimiterForm: FMT=Delimited["+ GetDelimiterForm.GD +"]\\This throws the error

                        H Offline
                        H Offline
                        Henry Minute
                        wrote on last edited by
                        #15

                        It is the double quote thing for Extended Properties that is causing the problem. In order to get a quotation mark within a literal string you have to 'escape them' This means that the double quotes in the middle have to look like \"\", for them to be recognised as quotes within a string. When this is all over look up Escape Characters for a better explanation. In the mean time take a look at ADO Connection Strings[^], for some examples. Search in the article for 'Extended Properties' and you'll see what I mean. Have a play. Good Luck! :)

                        Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                        B 2 Replies Last reply
                        0
                        • H Henry Minute

                          It is the double quote thing for Extended Properties that is causing the problem. In order to get a quotation mark within a literal string you have to 'escape them' This means that the double quotes in the middle have to look like \"\", for them to be recognised as quotes within a string. When this is all over look up Escape Characters for a better explanation. In the mean time take a look at ADO Connection Strings[^], for some examples. Search in the article for 'Extended Properties' and you'll see what I mean. Have a play. Good Luck! :)

                          Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                          B Offline
                          B Offline
                          bwood2020
                          wrote on last edited by
                          #16

                          Thank you Henry for all your help. I will look into this today.

                          1 Reply Last reply
                          0
                          • H Henry Minute

                            It is the double quote thing for Extended Properties that is causing the problem. In order to get a quotation mark within a literal string you have to 'escape them' This means that the double quotes in the middle have to look like \"\", for them to be recognised as quotes within a string. When this is all over look up Escape Characters for a better explanation. In the mean time take a look at ADO Connection Strings[^], for some examples. Search in the article for 'Extended Properties' and you'll see what I mean. Have a play. Good Luck! :)

                            Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                            B Offline
                            B Offline
                            bwood2020
                            wrote on last edited by
                            #17

                            Hi Henry, I have read a couple articles on escape sequences and have tried to include the same line of code(just modified to fit what I need) and I still get errors. Maybe I am looking in the wrong place but when I try and use Extended Properties=\"\"text;HDR=Yes;FMT=Delimited(" + gds + ");\"\";"; it says I need to add ";". But when I add one it tells me I need to add another. However, if I were to plug the line of code above into the code found in the Code Project page it seems fine. I think what is happening is that there is something wrong with the first part of the connection string, maybe the Source. "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @"; Could you look at this one more time for me and point me in the right direction when you have time please? Here is the entire connection string: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=\"\"text;HDR=Yes;FMT=Delimited(" + gds + ");\"\";"; Thank you, Brenton

                            H 1 Reply Last reply
                            0
                            • B bwood2020

                              Hi Henry, I have read a couple articles on escape sequences and have tried to include the same line of code(just modified to fit what I need) and I still get errors. Maybe I am looking in the wrong place but when I try and use Extended Properties=\"\"text;HDR=Yes;FMT=Delimited(" + gds + ");\"\";"; it says I need to add ";". But when I add one it tells me I need to add another. However, if I were to plug the line of code above into the code found in the Code Project page it seems fine. I think what is happening is that there is something wrong with the first part of the connection string, maybe the Source. "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @"; Could you look at this one more time for me and point me in the right direction when you have time please? Here is the entire connection string: String comString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" + Path.GetDirectoryName(FilePath) + @";Extended Properties=\"\"text;HDR=Yes;FMT=Delimited(" + gds + ");\"\";"; Thank you, Brenton

                              H Offline
                              H Offline
                              Henry Minute
                              wrote on last edited by
                              #18

                              I have found an article that is doing what I think you are trying to do. Read text file (txt, csv, log, tab, fixed length)[^], it only uses one \" instead of two. Have a look and see if it helps.

                              Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                              B 1 Reply Last reply
                              0
                              • H Henry Minute

                                I have found an article that is doing what I think you are trying to do. Read text file (txt, csv, log, tab, fixed length)[^], it only uses one \" instead of two. Have a look and see if it helps.

                                Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                                B Offline
                                B Offline
                                bwood2020
                                wrote on last edited by
                                #19

                                That did it Henry. Thank you so much. Is there something I need to do is far as closing this out or giving you a rating? Let me know and I will come back.

                                H 1 Reply Last reply
                                0
                                • B bwood2020

                                  That did it Henry. Thank you so much. Is there something I need to do is far as closing this out or giving you a rating? Let me know and I will come back.

                                  H Offline
                                  H Offline
                                  Henry Minute
                                  wrote on last edited by
                                  #20

                                  Thanks for the thanks! If you would just vote one of my posts as a 5, then people will know that your question has been answered. Good luck! :)

                                  Henry Minute Do not read medical books! You could die of a misprint. - Mark Twain Girl: (staring) "Why do you need an icy cucumber?" “I want to report a fraud. The government is lying to us all.”

                                  1 Reply Last reply
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