how can this program work correctly

[carter2000]

#include <iostream> using namespace std; class Test { public: Test() { } int GetValue() { return 2; } }; int main() { Test* test = new Test(); cout << test->GetValue() << endl; //test = NULL; delete test; cout << test->GetValue() << endl; system("pause"); return 0; } Output: 2 2 I'm a beginer.

[Stuart Dootson]

This works because executing GetValue doesn't access any part of a Test object. The function is resolved at compile time. It doesn't access any data members, so the fact that you've deleted the object doesn't affect the execution of the code. But even though this case works, don't do this in production code or anything...please.

Java, Basic, who cares - it's all a bunch of tree-hugging hippy cr*p

[_AnsHUMAN_]

Check this:

class Test
{
	int p;
public:
	Test()
	{
		p=2;
	}

	int GetValue()
	{
	return p;
	}
	~Test()
	{
	}
};

int main()
{
	Test* t1 = new Test();
	cout << t1->GetValue() <GetValue()<

Beware of the consequences of writing this type of code that you wrote You need to google first, if you have "It's urgent please" mentioned in your question. ;-)**_AnShUmAn_**

[carter2000]

Well i got it,and thank you for your help.

[ludi0423]

If you are using Visual Studio 2008, you may try #include "stdafx.h" #include using std::cout; using std::endl; class Test { public: Test() { } int GetValue() { return 2; } }; int main() { Test* test = new Test(); cout << test->GetValue() << endl; //test = NULL; delete test; cout << test->GetValue() << endl; system("pause"); return 0; } 1. add the "#include "stdafx.h"" before "include " 2. add the "using std::cout; using std::endl;"

[carter2000]

I consider the second GetValue would return a weird number, but it works to be 2. now i have got the answer. Thank you for your attention.

[_Superman_]

It will even work without ever calling the new operator.

Test* test = NULL;
test->GetValue();

Stuart gave you the reason for that.

«_Superman_» I love work. It gives me something to do between weekends.