button(visible&Enable) but CANNOT be pressed

[fitatc]

:confused:My qustion is Why this happened??? if sibling window paint by Z-order according to MSDN doc, the button should not be painted after the dialog. http://msdn.microsoft.com/en-us/library/dd183426(VS.85).aspx[^] -------------------------------------------------------------- Do the follow simple step you will see the "magic" button: 1. Create MFC SDI project 2. At [resouce view], Add a dialog and set style child.(WS_CHILD) 3. Add this code to the *view.cpp to create to child window:

    #define BTN1 10101
    int CTestView::OnCreate(LPCREATESTRUCT lpCreateStruct)
    {
     if (CView::OnCreate(lpCreateStruct) == -1)
      return -1;

     // TODO:  ここに特定な作成コードを追加してください。
      m\_dlg.Create(CTestDlg::IDD, this);
     m\_dlg.ShowWindow(SW\_SHOW);
     RECT rect;
     rect.left = 10;
     rect.top = 100;
     rect.right = 110;
     rect.bottom = 125;
     m\_btn.Create(\_T("testBtn"), WS\_VISIBLE | BS\_PUSHBUTTON, rect, this, BTN1);
     return 0;
    }

   \* CTestDlg m\_dlg, CButton m\_btn is member of the CTestView
   \* Z-order can be checked either by Spy++ or GetWindow API

You can fix the problem by add WS_CLIPSIBLINGS style of the button.

m_btn.Create(_T("testBtn"), WS_VISIBLE | BS_PUSHBUTTON | WS_CLIPSIBLINGS, rect, this, BTN1);

[Eric Haddan]

My guess is you should be creating the button in your m_dlg::OnCreate object, not in CTestView::OnCreate.

[fitatc]

thanks, Eric Haddan I use Button just to show the problem, it will be the same if two dialog created as child of CTestView The problem is: because sibling window paint in z-order(not as MSDN said), window in the lower order paint latter,makes window showed, but not active.