Sort Array in ascending and descding

[Lost User]

nt_virus wrote:

why is it so

You cannot print an array or integers directly in this way. You need to iterate the array and print each individual value after you have converted it to a character string. Take a look at some of the tutorials on the web.

[nt_virus]

thanks I did ascending..

public class Main{
public static void main(String[] args) {
int[] value = {2,1,3,6,5};
System.out.println("Unsorted value"); // Print unsorted array.
for (int s : value)
System.out.print(s + " ");
System.out.println("\n");
Arrays.sort(value); // Sort array

    System.out.println("sorted value ascending");       // Print unsorted array.
    for (int s : value)
        System.out.print(s + " ");
    System.out.println("\\n");      
}}

please tell how to do descending...

[Lost User]

nt_virus wrote:

please tell how to do descending...

Well I guess you need to look at the documentation for the Arrays.sort() method.

[nt_virus]

I read the documentation now, I didn't find descending. There is a way by Comparator .. but its lengthy .. Any other way .. please tell.

[Lost User]

nt_virus wrote:

There is a way by Comparator .. but its lengthy .. Any other way .. please tell.

You really think this[^] is lengthy? Or is it the reading of the documentation that's lengthy?

[nt_virus]

I tried that thing earlier but as I declared array as.. int[] value = {2,1,3,6,5} So this line Arrays.sort(value, Collections.reverseOrder()); giving error, red line under value, I don't understand why.. But now I declare array as .. Integer[] value = {2,1,3,6,5} It works....

/*
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package SortListOfNumbers;
import java.util.Arrays;
import java.util.Collections;

public class Main{
public static void main(String[] args)
{
Sorting srt = new Sorting();
srt.ascending();
srt.descending();
}
}
class Sorting{
public void ascending(){

        int\[\] value = {2,1,3,6,5};
        System.out.println("Sorting in ascending order");
        System.out.println("Unsorted value");       // Print unsorted array.
         for (int s : value)
           System.out.print(s + " ");
         System.out.println("\\n");
         Arrays.sort(value); // Sort in ascending
         System.out.println("sorted value ascending");       // Print unsorted array.
         for (int s : value)
                System.out.print(s + " ");
         System.out.println("\\n");
 }
 public void descending(){

        Integer\[\] value = {2,1,3,6,5};
        System.out.println("Sorting in descending order");
        System.out.println("Unsorted value");       // Print unsorted array.
         for (int s : value)
           System.out.print(s + " ");
         System.out.println("\\n");
         Arrays.sort(value, Collections.reverseOrder());
         System.out.println("Sorted Descending");       // Print unsorted array.
         for (int s : value)
           System.out.print(s + " ");
         System.out.println("\\n");
 }}

Please explain why is it happen so.. it bit strange for me. and thanks a lot.

[Lost User]

nt_virus wrote:

Please explain why is it happen so.. it bit strange for me.

Probably because int is a simple type, but Integer is a class. I would suggest reading the Java documentation for a full description of the differences and what methods and interfaces they support.

[4277480]

I looked at your code, you need to read the error message which says The method sort(int[]) in the type Arrays is not applicable for the arguments (int[], Comparator < Object > ) so when you added the Integer you are solving the problem that was generated because Integer class wraps a value of the primitive type int in an object. An object of type Integer contains a single field whose type is int.

[Lost User]

See further information below from Member 4277480.

[nt_virus]

Thanks a lot a lot to both of you guys.. You made my day..