array of differents types (possible?)

George Nistor

Hi, Now I use a driver (first part of the code) - no changes possible. I have to use something like a message processing and because I'm unable to use an array of the internal buffers of the driver -> I use more then 10 function with the same code. here is my code I would like to use a vector of messages (message0, message1 ..). any other ideea is welcome of grouping these data types. thanks <pre>// Gateway_array.cpp : Defines the entry point for the console application. // #include "stdafx.h" typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType0; typedef union { unsigned char _c[8]; msgType0 msg0_0; } buf0; buf0 message0; typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType1; typedef union { unsigned char _c[8]; msgType1 msg0_1; } buf1; buf1 message1; /// ................................ /// UP is the Driver .. No changes possible // X 8 times typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType; typedef union { unsigned char _c[8]; msgType msg; } type_array; type_array Vector[2]; // i would like to use a vector like this one int main(int argc, char* argv[]) { Vector[0] = message0; //error when using it return 0; } </pre>

CPallini

Why don't you define type_array as union of {buf1, .., buf8}? :)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]

George Nistor

Hi with a union like this doesn't work either. I get ..cannont convert buf0 to unsigned char. typedef union { buf0 msg0; buf1 msg1; } type_Array; type_Array Vector[]={message0 , message1}; if i put like this, works: unsigned char x1; unsigned char x2; type_Array Vector[]={x1, x2}; //(this doesn't seem to be logic i should have here a vector of 8 unsigned chars) so, the problem is the compiler see message0 of type buf0, somehow cannot use union definition. msgType0 and msgType1 are user defined types.

CPallini

Why you want to assign a unsigned char to a msgType0? It looks more reasonable something like

msgType0 msg;
unsigned char x = 0x20;
msg.signal0 = x;

:)

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]

George Nistor

yes, true my problem is I cannot build the array with this code: /// Driver typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType0; typedef union { unsigned char _c[8]; msgType0 msg0_0; } buf0; buf0 message0; typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType1; typedef union { unsigned char _c[8]; msgType1 msg0_1; } buf1; buf1 message1; /// ................................ /// UP is the Driver .. No changed possible // X 8 times // seems logic to work with this code typedef union { buf0 msg0; buf1 msg1; } type_Array; type_Array Vector[]={message0 , message1}; so, I want to build an array of message0, message1.... not other data.

George Nistor

hi the ideea was ok. my sintax was not this code is ok: // diff types array.cpp : Defines the entry point for the console application. // #include "stdafx.h" typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType0; typedef union { unsigned char _c[8]; msgType0 msg0_0; } buf0; buf0 message0; typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType1; typedef union { unsigned char _c[8]; msgType1 msg0_1; } buf1; buf1 message1; /// ................................ /// UP is the Driver .. No changed possible // X 8 times int main(int argc, char* argv[]) { printf("Hello World!\n"); typedef union { buf0 msg0; buf1 msg1; } type_Array; type_Array X1; type_Array X2; X1.msg0= message0; X2.msg1= message1; type_Array Vector[2]; Vector[0]= X1; Vector[1]= X2; return 0; }

George Nistor

hi (again what I would like to have is an array of message0, message1...) please give me a clue if any I thought I solved it.. unfortunally I cannot refer the buffer I need. I need message0._c[0] these buffer to refer to. the only way is with sintax: Vector[0].msg0._c[0]=1; //ok // not usefull i have to apppend .msg0 which is not usefull // diff types array.cpp : Defines the entry point for the console application. // #include "stdafx.h" typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType0; typedef union { unsigned char _c[8]; msgType0 msg0_0; } buf0; buf0 message0; typedef struct { unsigned char signal7 : 8; unsigned char signal6 : 8; unsigned char signal5 : 8; unsigned char signal4 : 8; unsigned char signal3 : 8; unsigned char signal2 : 8; unsigned char signal1 : 8; unsigned char signal0 : 8; } msgType1; typedef union { unsigned char _c[8]; msgType1 msg0_1; } buf1; buf1 message1; /// ................................ /// UP is the Driver .. No changed possible // X 8 times int main(int argc, char* argv[]) { printf("Hello World!\n"); union type_Array { buf0 msg0; buf1 msg1; } ; type_Array X1; type_Array X2; X1.msg0= message0; X2.msg1= message1; type_Array Vector[2]; Vector[0]= X1; Vector[1]= X2; // what i would like to refer is this buffer message0._c[0] message0._c[0]= 1; Vector[0]._c[0]=1; //imposible to use because of refering msg0 //Vector[0].msg0._c[0]=1; //ok // not usefull return 0; }

modified on Thursday, January 21, 2010 11:34 AM

CPallini · modified on Thursday, January 21, 2010 11:34 AM

Why isn't it useful? A dirty trick would be

union type_Array
{
unsigned char _c[8];
buf0 msg0;
buf1 msg1;
} ;

If the Lord God Almighty had consulted me before embarking upon the Creation, I would have recommended something simpler. -- Alfonso the Wise, 13th Century King of Castile.
This is going on my arrogant assumptions. You may have a superb reason why I'm completely wrong. -- Iain Clarke
[My articles]

George Nistor

isn't usefull either because I have to modify the driver. The upper section until // /// UP is the Driver .. No changes possible // X 8 times I cannot modify! because of these individual buffers of the driver ... insted of writing a SINGLE! Processing message function - for all messaging (involving these individual buffers) (it is the same code) - I have a dozen function making same thing. Inside them I refer to buffers like message0._c[(i=1,n)]= value; , next function message1._c[(i=1,n)]= value etc. If i would have an ARRAY of message0, message1, I would write a single function. with my previous code I would refer these buffers with Vector[0].msg0._c[0]=1; //ok // not usefull But how do I put in the code line section msg0? the above line would be in a for. Maybe I was more clear explaiing my problem this time. I think the problem here is, basically I have a union inside a union.