سیما
C#
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تقدیم به سیما
تابع مورد نظر
Public Function changeNum(ByVal Number As Double) As Double Dim numDouble As Double Dim num As String Dim TestArray() As String = Split(Number.ToString(), ".") num = TestArray(1) + "." + TestArray(0) numDouble = CDbl(num) Return numDouble End Function
روش فراخوانی
Dim testnum As Double = changeNum(12.5)
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این را فقط کپی کن
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تقدیم به سیما
تابع مورد نظر
Public Function changeNum(ByVal Number As Double) As Double Dim numDouble As Double Dim num As String Dim TestArray() As String = Split(Number.ToString(), ".") num = TestArray(1) + "." + TestArray(0) numDouble = CDbl(num) Return numDouble End Function
روش فراخوانی
Dim testnum As Double = changeNum(12.5)
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Public Class Form1 Public Function changeNum(ByVal Number As Double) As Double Dim numDouble As Double Dim num As String Dim TestArray() As String = Split(Number.ToString(), ".") num = TestArray(1) + "." + TestArray(0) numDouble = CDbl(num) Return numDouble End Function Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim testnum As Double = changeNum(12.5) End Sub End Class
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حل شد
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Public Class Form1 Public Function changeNum(ByVal Number As Double) As Double Dim numDouble As Double Dim num As String Dim TestArray() As String = Split(Number.ToString(), ".") num = TestArray(1) + "." + TestArray(0) numDouble = CDbl(num) Return numDouble End Function Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim testnum As Double = changeNum(12.5) End Sub End Class
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حل شد
Translate: It is solved.
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Translate : Sweety forget them, just mail your photograph , I'm looking forward to see your photograph.
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Translate: Honey , The error has occurred on line four. Doesn't need to write something in App's form ?
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این را فقط کپی کن
Translate : Just copy this one.