How to add XmlInclude attribute dynamically

[Anindya Chatterjee]

I have the following classes

[XmlRoot]
public class AList
{
public List<B> ListOfBs {get; set;}
}

public class B
{
public string BaseProperty {get; set;}
}

public class C : B
{
public string SomeProperty {get; set;}
}

public class Main
{
public static void Main(string[] args)
{
var aList = new AList();
aList.ListOfBs = new List<B>();
var c = new C { BaseProperty = "Base", SomeProperty = "Some" };
aList.ListOfBs.Add(c);

    var type = typeof (AList);
    var serializer = new XmlSerializer(type);
    TextWriter w = new StringWriter();
    serializer.Serialize(w, aList);
}    

}

Now when I try to run the code I got an InvalidOperationException at last line saying that The type XmlTest.C was not expected. Use the XmlInclude or SoapInclude attribute to specify types that are not known statically. I know that adding a [XmlInclude(typeof(C))] attribute with [XmlRoot] would solve the problem. But I want to achieve it dynamically. Because in my project class C is not known prior to loading. Class C is being loaded as a plugin, so it is not possible for me to add XmlInclude attribute there. I tried also with

TypeDescriptor.AddAttributes(typeof(AList), new[] { new XmlIncludeAttribute(c.GetType()) });

before

var type = typeof (AList);

but no use. It is still giving the same exception. Does any one have any idea on how to achieve it?

Regards, Anindya Chatterjee[^]