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  4. Find an algorithm

Find an algorithm

Scheduled Pinned Locked Moved Algorithms
algorithmsdebuggingregexquestionlearning
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  • F frank33

    have you tried a Karnaugh map?

    Frank

    N Offline
    N Offline
    Not Active
    wrote on last edited by
    #20

    You mean like Member 4190501 suggested over 10 hours ago. If you also read the responses you would see the problem was solved long ago.


    I know the language. I've read a book. - _Madmatt

    1 Reply Last reply
    0
    • N Not Active

      It seemed to be clear to everyone else


      I know the language. I've read a book. - _Madmatt

      G Offline
      G Offline
      grgran
      wrote on last edited by
      #21

      Ok, wow ... ummmm, your welcome?

      1 Reply Last reply
      0
      • N Not Active

        I've probably been staring at this far too long but I can't find an algorithm that will return the correct results for the code below. Anyone have some fresh ideas?

        private void Test()
        {
        Logic(false, false, false, false, false, false, false);
        Logic(false, false, false, false, true, true, true);
        Logic(false, false, false, false, true, false, false);
        Logic(false, false, true, false, true, true, false);
        Logic(false, false, true, true, true, true, true);
        }

        private void Logic(bool f, bool fl, bool d, bool dl, bool r, bool rl, bool expected)
        {
        bool result = [What algorithm goes here];

        System.Diagnostics.Debug.Assert(result == expected, "Does not match expected results");
        

        }


        I know the language. I've read a book. - _Madmatt

        A Offline
        A Offline
        ashishpahlaz
        wrote on last edited by
        #22

        result = ((f&&f1) || (d&&d1) || (r&&r1)) && (f||f1) && (d||d1) && (r||r1)

        L 1 Reply Last reply
        0
        • A ashishpahlaz

          result = ((f&&f1) || (d&&d1) || (r&&r1)) && (f||f1) && (d||d1) && (r||r1)

          L Offline
          L Offline
          Luc Pattyn
          wrote on last edited by
          #23

          incorrect, none of the test cases have (f||f1) true. :|

          Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

          Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

          A 1 Reply Last reply
          0
          • L Luc Pattyn

            incorrect, none of the test cases have (f||f1) true. :|

            Luc Pattyn [Forum Guidelines] [Why QA sucks] [My Articles] Nil Volentibus Arduum

            Please use <PRE> tags for code snippets, they preserve indentation, and improve readability.

            A Offline
            A Offline
            ashishpahlaz
            wrote on last edited by
            #24

            result = ((f&&f1) || (d&&d1) || (r&r1)) && (f==f1) && (d==d1) && (r==r1);

            1 Reply Last reply
            0
            • N Not Active

              I've probably been staring at this far too long but I can't find an algorithm that will return the correct results for the code below. Anyone have some fresh ideas?

              private void Test()
              {
              Logic(false, false, false, false, false, false, false);
              Logic(false, false, false, false, true, true, true);
              Logic(false, false, false, false, true, false, false);
              Logic(false, false, true, false, true, true, false);
              Logic(false, false, true, true, true, true, true);
              }

              private void Logic(bool f, bool fl, bool d, bool dl, bool r, bool rl, bool expected)
              {
              bool result = [What algorithm goes here];

              System.Diagnostics.Debug.Assert(result == expected, "Does not match expected results");
              

              }


              I know the language. I've read a book. - _Madmatt

              T Offline
              T Offline
              Tadeusz Westawic
              wrote on last edited by
              #25

              Is it simply the number of TRUE arguments passed? No TRUE args ==> FALSE even no of TRUE args ==> TRUE Otherwise ==> FALSE :confused: Tadeusz Westawic Sum quid sum.

              N 1 Reply Last reply
              0
              • N Not Active

                I've probably been staring at this far too long but I can't find an algorithm that will return the correct results for the code below. Anyone have some fresh ideas?

                private void Test()
                {
                Logic(false, false, false, false, false, false, false);
                Logic(false, false, false, false, true, true, true);
                Logic(false, false, false, false, true, false, false);
                Logic(false, false, true, false, true, true, false);
                Logic(false, false, true, true, true, true, true);
                }

                private void Logic(bool f, bool fl, bool d, bool dl, bool r, bool rl, bool expected)
                {
                bool result = [What algorithm goes here];

                System.Diagnostics.Debug.Assert(result == expected, "Does not match expected results");
                

                }


                I know the language. I've read a book. - _Madmatt

                F Offline
                F Offline
                fjdiewornncalwe
                wrote on last edited by
                #26

                ( ( d && dl ) && ( r && rl ) ) || ( (d && dl) && ( !r && !rl) ) || ( (!d && !dl) && ( r && rl ) )

                I wasn't, now I am, then I won't be anymore.

                N 1 Reply Last reply
                0
                • T Tadeusz Westawic

                  Is it simply the number of TRUE arguments passed? No TRUE args ==> FALSE even no of TRUE args ==> TRUE Otherwise ==> FALSE :confused: Tadeusz Westawic Sum quid sum.

                  N Offline
                  N Offline
                  Not Active
                  wrote on last edited by
                  #27

                  What are you confused about? Perhaps you are confused that the problem had been solved 18 days ago by people how were not confused.:confused:


                  I know the language. I've read a book. - _Madmatt

                  T 1 Reply Last reply
                  0
                  • F fjdiewornncalwe

                    ( ( d && dl ) && ( r && rl ) ) || ( (d && dl) && ( !r && !rl) ) || ( (!d && !dl) && ( r && rl ) )

                    I wasn't, now I am, then I won't be anymore.

                    N Offline
                    N Offline
                    Not Active
                    wrote on last edited by
                    #28

                    Only 18 days after everyone else. Glad it wasn't urgentz


                    I know the language. I've read a book. - _Madmatt

                    F 1 Reply Last reply
                    0
                    • N Not Active

                      What are you confused about? Perhaps you are confused that the problem had been solved 18 days ago by people how were not confused.:confused:


                      I know the language. I've read a book. - _Madmatt

                      T Offline
                      T Offline
                      Tadeusz Westawic
                      wrote on last edited by
                      #29

                      There are unanswered posts of my own that are months old and I would still appreciate any other point of view as long as it is mathematically valid and programmable. Are you saying my post is illegal? Take off that heavy badge once in a while. Tadeusz Westawic Sum quid sum.

                      N 1 Reply Last reply
                      0
                      • N Not Active

                        Only 18 days after everyone else. Glad it wasn't urgentz


                        I know the language. I've read a book. - _Madmatt

                        F Offline
                        F Offline
                        fjdiewornncalwe
                        wrote on last edited by
                        #30

                        :laugh: I didn't even notice that. Man, do I suck... :-D

                        I wasn't, now I am, then I won't be anymore.

                        1 Reply Last reply
                        0
                        • T Tadeusz Westawic

                          There are unanswered posts of my own that are months old and I would still appreciate any other point of view as long as it is mathematically valid and programmable. Are you saying my post is illegal? Take off that heavy badge once in a while. Tadeusz Westawic Sum quid sum.

                          N Offline
                          N Offline
                          Not Active
                          wrote on last edited by
                          #31

                          Tadeusz Westawic wrote:

                          There are unanswered posts of my own

                          There is the difference. This post was answered by several people quite a long time ago.

                          Tadeusz Westawic wrote:

                          Are you saying my post is illegal?

                          losen up and perhaps vist more often


                          I know the language. I've read a book. - _Madmatt

                          1 Reply Last reply
                          0
                          • N Not Active

                            I've probably been staring at this far too long but I can't find an algorithm that will return the correct results for the code below. Anyone have some fresh ideas?

                            private void Test()
                            {
                            Logic(false, false, false, false, false, false, false);
                            Logic(false, false, false, false, true, true, true);
                            Logic(false, false, false, false, true, false, false);
                            Logic(false, false, true, false, true, true, false);
                            Logic(false, false, true, true, true, true, true);
                            }

                            private void Logic(bool f, bool fl, bool d, bool dl, bool r, bool rl, bool expected)
                            {
                            bool result = [What algorithm goes here];

                            System.Diagnostics.Debug.Assert(result == expected, "Does not match expected results");
                            

                            }


                            I know the language. I've read a book. - _Madmatt

                            R Offline
                            R Offline
                            Radhakrishnan G
                            wrote on last edited by
                            #32

                            private void Logic( bool f1, bol f2, bool f3, bool f4, bool f5, bool f6, bool expected)
                            {
                            bool result = ((!f1) && (!f2) && f5 && f6 && ( ((!f3) && (!f4)) || ( f3 && f4 )));
                            System.Diagnostics.Debug.Assert( result == expected, "Does not match expected results" );
                            }

                            1 Reply Last reply
                            0
                            • N Not Active

                              I've probably been staring at this far too long but I can't find an algorithm that will return the correct results for the code below. Anyone have some fresh ideas?

                              private void Test()
                              {
                              Logic(false, false, false, false, false, false, false);
                              Logic(false, false, false, false, true, true, true);
                              Logic(false, false, false, false, true, false, false);
                              Logic(false, false, true, false, true, true, false);
                              Logic(false, false, true, true, true, true, true);
                              }

                              private void Logic(bool f, bool fl, bool d, bool dl, bool r, bool rl, bool expected)
                              {
                              bool result = [What algorithm goes here];

                              System.Diagnostics.Debug.Assert(result == expected, "Does not match expected results");
                              

                              }


                              I know the language. I've read a book. - _Madmatt

                              R Offline
                              R Offline
                              RobCroll
                              wrote on last edited by
                              #33

                              yeah I know it was answered a while ago but here is a slightly more elegant algorithm bool result = (f == fl) && (d == dl) && (r == rl) ? f | d | r : false; or in a less descriptive form bool result = f == fl && d == dl && r == rl && f | d | r;

                              modified on Tuesday, November 9, 2010 6:28 PM

                              N 1 Reply Last reply
                              0
                              • R RobCroll

                                yeah I know it was answered a while ago but here is a slightly more elegant algorithm bool result = (f == fl) && (d == dl) && (r == rl) ? f | d | r : false; or in a less descriptive form bool result = f == fl && d == dl && r == rl && f | d | r;

                                modified on Tuesday, November 9, 2010 6:28 PM

                                N Offline
                                N Offline
                                Not Active
                                wrote on last edited by
                                #34

                                Such a timely response :rolleyes:


                                I know the language. I've read a book. - _Madmatt

                                R 1 Reply Last reply
                                0
                                • N Not Active

                                  Such a timely response :rolleyes:


                                  I know the language. I've read a book. - _Madmatt

                                  R Offline
                                  R Offline
                                  RobCroll
                                  wrote on last edited by
                                  #35

                                  Well I teach at college so I didn't want to think I was doing your homework for you. ;P

                                  N 1 Reply Last reply
                                  0
                                  • R RobCroll

                                    Well I teach at college so I didn't want to think I was doing your homework for you. ;P

                                    N Offline
                                    N Offline
                                    Not Active
                                    wrote on last edited by
                                    #36

                                    Robert Croll wrote:

                                    Well I teach at college

                                    What course do you teach, procrastination?


                                    I know the language. I've read a book. - _Madmatt

                                    R 1 Reply Last reply
                                    0
                                    • N Not Active

                                      Robert Croll wrote:

                                      Well I teach at college

                                      What course do you teach, procrastination?


                                      I know the language. I've read a book. - _Madmatt

                                      R Offline
                                      R Offline
                                      RobCroll
                                      wrote on last edited by
                                      #37

                                      :laugh: :laugh: Can I get back to you on that?

                                      1 Reply Last reply
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