hello, i have a question about char and int

[lxlenovostar]

hello everyone, i still understand this question: char a = '1'; printf("%d",a ); //can get 49 printf("%c",a ); //can get 1 how can i know why it can printf 49?? somethings have between about char and int ?????? thank you

[Cool_Dev]

See here what is the Ascci decimal for character '1'. Hope you get a clue on how characters are stored in memory while using 8 bit char datatype. Otherwise go for some good books. :(

[Lost User]

printf("%d",a ); //can get 49

This line says print the decimal value of variable a; since a contains the character '1' it prints the ASCII value, which is 0x31 or 49 decomal.

printf("%c",a ); //can get 1

This says print the character stored in variable a, which is the character '1'.

Just say 'NO' to evaluated arguments for diadic functions! Ash