XPathNavigator iterate and write

[Mark F]

I am using XPathNavigator to sort nodes by name. Is there a method for writing the sorted nodes to the same or different file?

        foreach( XPathNavigator item in navigator.Select( expr ) )
        {
             // write to new document here...,
        }

Thanks, Mark

[cechode]

How about something like this?

    static void Main(string\[\] args)
    {
        XDocument x = XDocument.Parse(sXml);
        Reorder(x.FirstNode);
        x.Save(newFileName);
    }

    private static void Reorder(XNode node)
    {
        var kids = (from nd in node.XPathSelectElements("\*") orderby nd.Name.LocalName select nd).ToList();
        if (kids.Count>1)
        {
            (node as XElement).ReplaceNodes(kids);
        }
        kids.ForEach(f => Reorder(f));
    }

[Mark F]

The xml is displayed in a TreeView control so alphabetical sorting by 'name' attribute was necessary. I worked out something similar to your reply and problem solved. Haven't had a prior occasion to use Linq however. Thanks for the help!

modified on Friday, December 3, 2010 3:28 PM

[cechode]

of course not. ( there are several ways as you'd expect, heres one, not the best not the worst ) how's this ?

    static void Main(string\[\] args)
    {
        string newFileName = "c:\\\\myfilename.xml";

        XmlDocument docSource = new XmlDocument();
        docSource.LoadXml(XML);
        Reorder(docSource.DocumentElement);
        docSource.Save(newFileName);
    }


    private static void Reorder(XmlNode node)
    {
        SortedList childlist = SortedChildNodes(node);
        node.RemoveAll();
        for (int i = 0; i < childlist.Count; i++)
        {
            Reorder(node.AppendChild(childlist.Values\[i\]));
        }

    }
    static SortedList SortedChildNodes(XmlNode node)
    {
        SortedList ret = new SortedList();
        for (int i = 0; i < node.ChildNodes.Count; i++)
        {
            string name = node.ChildNodes\[i\].Name;
            XmlNode nd = node.ChildNodes\[i\];
            ret.Add(name, nd);
        }
        return ret;
    }