Extract XML values using XpathNavigator

[baranils]

Hello Is there a way to extract some values from an XML node using the XmlPathNavigator ? I need to extrat information from a XML file. I was first trying to use an XmlTextReader but the pure sequential access seeme a bit tedious to handle So I was trying to use the XpathDocument I use a XPathNavigator to browse each node of my document (see code below) But for each product I just need to extract a few information - Brand - Model - ID (there are a lot of other unneeded information) Is it possible to do that with the XpathNavigator ? Or do I need another approach ? Obviously I can write my own parser but I can't believe that there is no simple way with standard classes ? Thanks for any help !

  XPathDocument xmldoc = new XPathDocument(p);
  XPathNavigator nav = xmldoc.CreateNavigator();
  int j = 0;
  foreach (XPathNavigator product in nav.Select("liste/mobile"))
  {
    j++;
  }

[PIEBALDconsult]

Probably, but I've never used one. I use an XmlDocument; the SelectNodes and SelectSingleNode methods use XPath.

[baranils]

Thanks I finaly found some solution The first think to care is also the granularity In my case every product embed a bloc_im node that contains everything So the first select must be on "liste/product/bloc_im" I was first doing "liste/product" and it take me a while to understand that first issue !

  foreach (XPathNavigator product in nav.Select("liste/product/bloc\_im"))
  {

    string refORF = product.SelectSingleNode("ref").Value;
    string IdORF = product.SelectSingleNode("id").Value;
    string Brand= product.SelectSingleNode("Brand").Value;
    string modele = product.SelectSingleNode("model").Value;

    sw.WriteLine("{0}\\t{1}\\t{2}\\t{3}",Id,ref,Brand,modele);

    XPathNavigator xNav = product.SelectSingleNode("TACS");
    foreach (XPathNavigator xNav1 in xNav.Select("TAC"))
    {
      string Tac = xNav1.Value;
    }

    j++;
  }

[Abhinav S]

xmlDoc.SelectSingleNode(liste/mobile); should give the same results.

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[Alan Balkany]

I've just discovered LINQ to XML, which makes processing XML files very easy. You only need two classes (which become available when you have using System.Xml.Linq): XDocument and XElement. XDocument opens the XML file. XElement is the type of each node in the XML tree. Some of the XElement methods return a nice IEnumerable list that you can process with foreach. There's a lot more to LINQ to XML, but just these two classes enable you to easily do basic processing.