Easy question:

[Sunnygirl]

hello @all, i have: char r1[1000]; how can i delete the char r1??? thanks you sunny

[Chris Losinger]

you can't "delete" something that you didn't create with "new". -c

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WWT2D?

Fractals

[georgiek50]

If you mean clearing out the array do this: r1[0] = '\0'; (All clear!)

[Harold Bamford]

georgiek50 wrote: If you mean clearing out the array do this: r1[0] = '\0'; (All clear!) This assumes you are using r1 as a character string rather than an array of bytes. If you want to "clear out" an array, try:

memset(r1,0,1000);  // where 1000 is the number of bytes in r1

[georgiek50]

Even though it is an array of byte wouldn't \0 take care of everything? which brings me to ask another question. If I declared an array of bytes say array[100] but then only needed to fill the first fifty. Do I need a NULL character like in a string? If yes how would I set it. If no, why not?

[Harold Bamford]

georgiek50 wrote: Even though it is an array of byte wouldn't \0 take care of everything? which brings me to ask another question. If I declared an array of bytes say array[100] but then only needed to fill the first fifty. Do I need a NULL character like in a string? If yes how would I set it. If no, why not? I didn't make myself clear. If you are using the array of bytes as a null-terminated cstring: strcpy(r1,"This is a string"); Then terminating at the "zero'th" position will clear out the string. For example, if you said:

strcpy(r1,"0123456789 This is a string");
r1[15] = 0;
printf("%s\n", r1);

The output would be "0123456789 This" If you then dumped the first 20 bytes of r1:

for(int i = 0; i < 20; i++)
{
   printf("0x%02X ", r1[i]);
}

You would get something like: 0x30 0x31 0x32 ... 0x39 0x20 0x54 0x68 0x69 0x73 **0x00** 0x69 0x73 ... That's the convention for null-terminated cstrings (not to be confused with CString); a 0 terminates the string. If it is just an array of bytes, then 0 is just another value.

[georgiek50]

Ok, I see what you're saying now.